Q: How do you use continuous division method to find the gcf of 12 and15?

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8

It doesn't matter what method you use, you need at least two numbers to find a GCF.

The GCF is 7.The LCM is 70.

It is 3 because 9/3 = 3 and 12/4 = 3

30/2 = 15/3 = 5/5 = 1 2 x 3 x 5 = 30

by long division

216 ,4587 and 2378

Two or more numbers are needed to find their LCM

Two or more numbers are needed to find their LCM

all you have to do is find the "least common multiple" witch is also the leats common denomenator

i don't kniw

Divide by 3 multiply by 2

To start, factor 195 and 299 into prime factors: 195 = 3*5*13 299 = 13*23 13 is the only shared factor, so it is the GCF.

32 is even so it is divisible by 2. If you keep dividing it by 2 you will find that 32 is 2 to the 5th power, i.e. 2 * 2 * 2 * 2 * 2. That's the answer.

You need at least two numbers to find a GCF whatever method you use.

The greatest common factor of 49 and 77 is 7, no matter what method you useto find it.If you solve the same problem twice, using two different methods, and get twodifferent answers, then at least one of the answers is wrong, and there's a goodchance that they both are.

58/2 = 29/29 = 1 82/2 = 41/41 = 1 2 x 29 = 58 2 x 41 = 82 Select the common factor. The GCF is 2.

The square root of 366,025 is 605. I don't know the division method, but that doesn't matter. The result is the same no matter what method you use to find it. If you work the same problem by two different methods and get two different answers, then at least one of them is wrong, and there's a good chance that they both are.

We will find the continuous division of 20 you can only divide prime nunbers like 2,3,5,7,11,13,17,19,23 and more SOLUTION: 5[13 13[13 Why is it double thirteen? because thirteen is a prime number ANSWER: 20=5x13 If it is double 13 or 5 for an short anwer or we call it exponential form 20=5 2 two is small at the top ,x13 2two is small at the top That's the answer thankyou! and don't stop dividing until you get one!

If this is in the context of finding a root of an equation, the answer is to make some guesses. Find value x1 and x2 such that f(x1) and f(x2) have opposite signs. Then, provided that f is a continuous function over (x1, x2), the bisection method will find its root.

GCF- 8 16 2 8 16 2 4 8 2 2 4 1 2

Find the LCM of the first two numbers and then find the LCM of that number and the third one. That answer will be the LCM of all three.

You do the division!

73

A continuous spectrum is seen in a rainbow.