Q: How do you use four 6s to make 2?

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If you mean 4/6 then it is equivalent to 2/3

-2/2-2/2 = -2

One orbital - 6s which can hold 2 electrons.

(s + 6)(6s - 7)

13s - 2

Is done by (3/3) plus (3/3) = 2

3 x (22)2 + 2 = 50

76 and 1/2 of them.

4 6s = 4*6 = 24. As a fraction, this can be written as 24/1.

25 of them with a remainder of 2

The maximum number of electrons that can occupy and s subshell, or sublevel, is 2. So the maximum number of electrons that can occupy the 6s subshell is 2.

4/6 = 2/3

3x3=9... 9-3=6.... 6/3=2 !

I have a 2005 Mazda 6s. It has four O2s. One in each exhaust manifold and one just below each catalytic converter connected to each exhaust manifold. Simply said 2 behind the radiator and 2 in front of the firewall. Have fun. If you didn't know, the 2005 Mazda 6s (V6) has four catalytic converters. One on each exhaust manifold and two more before the muffler. Go figure!

3/3 + 3/3 = 6/3 = 2

[Xe]6s^2

It is [Xe] 6s^2

2 + 2 + 2 + 2 = 8

Ceseum, 55Cs, has just 1 '6s' electron: 2, 8, 18, 18, 8, 1 electrons in the 1st to 6st shell respectevely.

[Xe] 5d^1 6s^2

[Xe] 4f 12 6s 2

8 if them with a remainder of 2

3 jacks and two 6s is better then 3 6s and 2 jacks :)

22 ÷ 2 - 2 = 9

Pb (lead)

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