Q: How can i use four 2s and one 3 to make 50?

Write your answer...

22x2x2 is 88

There are four 2s in a deck of cards, one of each suit.

Yes

You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26

2 + 2 + 2 + 2 = 8

Four 2s make 8, so 25% is your answer

22/2 - 2

If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.

Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42

Yes: 2 x 2 x 2 + 2!

2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)

lithium atom is just a ball it has 1s and 2s orbitals both of which are spheres the 1s is occupied by two electrons and the 2s one electron

36

2+ (2-2)x2 = 2

The 2s is one orbital, it can contain up to two electrons, one spin up one spin down.

2s.3s

22+22

you do 2 + 2

There are four 2s in a deck of cards.

four 6 1/2s.

Lithium

2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17

64 ÷ 2 = 32

Yes. It's 22 x 2 ÷ 2

[He] 2s one