If you mean 4/6 then it is equivalent to 2/3
One orbital - 6s which can hold 2 electrons.
-2/2-2/2 = -2
(s + 6)(6s - 7)
13s - 2
76 and 1/2 of them.
Is done by (3/3) plus (3/3) = 2
4 6s = 4*6 = 24. As a fraction, this can be written as 24/1.
25 of them with a remainder of 2
3 x (22)2 + 2 = 50
16
The maximum number of electrons that can occupy and s subshell, or sublevel, is 2. So the maximum number of electrons that can occupy the 6s subshell is 2.