0
If you are using 1/3 of x in an equation with an equal sign, you should multiply by three on both sides so the 1/3 is canceled because 1/3 x 3 = 1, so you will get 1x. You can also use this for other fractions, like if you have 1/5, you can multiply by 5 on both sides. Here's an example.
1/5 x = 20 Multiply by 5 on both sides, so you get
5/5x = 100 which simplifies to
x = 100.
Hope this helps!
What else can I help you with?
How do you solve 2 equals x- one third y?
You can't. You need 2 equations to solve for 2 unknowns
What is X to the power of one third times x to the third?
In this case, you can use a single power, with "x" as the base, and add the exponents,
What is one-third of x?
one-third of x is x/3
Divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 4?
One part is 63.6 and the other part is 120.4 Let x be one part and y be the other part. (1/3)X = (1/7)Y + 4 ... one third of one part can exceed one-seventh of the other part by 4. X + Y = 184 So you have two equations and two unknowns: X + Y = 184 (1/3)X - (1/7)Y = 4 After rerranging and solving the simlutaneous equations, you get X = 63.6 and Y = 120.4
Are what equations express two variables in terms of a third variable called the parameter?
Parametric equations. e.g. x = f(t) y = g(t)
What is the value of X and Y 3-2i - X plus Yi plus 2-3i?
To find the values of X and Y you need two independednt linear equations. There are no equations given, only an expression involving a third variable, i
What times what is 18 that adds up to -25?
-7
Two numbers sum to 50 their difference is 16 what are two equations for this problem?
x + y = 50 x - y = 16 --------------- (add the two equations to solve for x) 2x = 66 x = 33 then substitute x into one of the above equations to get y = 17
How can you use substitution method to solve a system of equations that does not have a variable with a coefficient of 1 or - 1?
To use the substitution method on a system of equations without a variable with a coefficient of 1 or -1, you first isolate one variable in one of the equations. For instance, if you have the equations (2x + 3y = 6) and (4x - y = 5), you can solve the first equation for (y), resulting in (y = (6 - 2x)/3). Next, substitute this expression for (y) into the second equation, allowing you to solve for (x). Finally, substitute the value of (x) back into one of the original equations to find the corresponding value of (y).
Which one of the following equations represents the y- axis?
X = 0
How do you find x and y in system of equations?
The basic idea here is to look at both equations and solve for either x or y in one of the equations. Then plug the known value into the second equation and solve for the other variable.
You are given two equations which are both true and you are asked to solve for both x and y You plan to solve this set of equations by substituting part of one equation into the other so you end up?
(a) rearrange one of the equations so that x or y is alone on one side of the equals sign.
