If you are using 1/3 of x in an equation with an equal sign, you should multiply by three on both sides so the 1/3 is canceled because 1/3 x 3 = 1, so you will get 1x. You can also use this for other fractions, like if you have 1/5, you can multiply by 5 on both sides. Here's an example.
1/5 x = 20 Multiply by 5 on both sides, so you get
5/5x = 100 which simplifies to
x = 100.
Hope this helps!
You can't. You need 2 equations to solve for 2 unknowns
In this case, you can use a single power, with "x" as the base, and add the exponents,
one-third of x is x/3
One part is 63.6 and the other part is 120.4 Let x be one part and y be the other part. (1/3)X = (1/7)Y + 4 ... one third of one part can exceed one-seventh of the other part by 4. X + Y = 184 So you have two equations and two unknowns: X + Y = 184 (1/3)X - (1/7)Y = 4 After rerranging and solving the simlutaneous equations, you get X = 63.6 and Y = 120.4
Parametric equations. e.g. x = f(t) y = g(t)
To find the values of X and Y you need two independednt linear equations. There are no equations given, only an expression involving a third variable, i
-7
x + y = 50 x - y = 16 --------------- (add the two equations to solve for x) 2x = 66 x = 33 then substitute x into one of the above equations to get y = 17
X = 0
The basic idea here is to look at both equations and solve for either x or y in one of the equations. Then plug the known value into the second equation and solve for the other variable.
(a) rearrange one of the equations so that x or y is alone on one side of the equals sign.
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.