x + y = 50
x - y = 16
--------------- (add the two equations to solve for x)
2x = 66
x = 33
then substitute x into one of the above equations to get y = 17
Let the two numbers be x and y. According to the problem, we have the equations: x + y = 2500 and x - y = 718. Solving these simultaneously, we can add the two equations to get 2x = 3218, which gives x = 1609. Substituting x back into the first equation, we find y = 2500 - 1609 = 891. Thus, the two numbers are 1609 and 891.
Let the two numbers be ( x ) and ( y ). From the information given, we can set up the equations: ( x - y = 10 ) and ( x + y = 14 ). Solving these equations, we find that ( x = 12 ) and ( y = 2 ). Thus, the two numbers are 12 and 2.
To find two numbers that equal a sum of 7 and a difference of 1, let’s denote the numbers as ( x ) and ( y ). From the information given, we can set up the equations: ( x + y = 7 ) and ( x - y = 1 ). Solving these equations, we find that ( x = 4 ) and ( y = 3 ). Thus, the two numbers are 4 and 3.
I think you mean product... 4 and 9
Suppose the two numbers are X and Y Then X - Y = 6 and X + Y = 14 Adding the two equations gives 2X = 20 so that X = 10 And substituting this value into one of the equations, Y = 4 The two numbers are 10 and 4.
First, we need to clarify the condition in the problem: the sum of two numbers is 16, and the difference between the two numbers is 6. Based on these conditions, we can say that these two numbers are respectively x and y. According to the problem description, we can list the following equations: The sum of the two numbers is 16, which is x plus y is equal to 16. The difference between the two numbers is 6, which is 6 x−y=6. By solving this system of equations, we get x=9 and y=7. So the product of these two numbers is 9 x 7 = 63
Let the two numbers be x and y. According to the problem, we have the equations: x + y = 2500 and x - y = 718. Solving these simultaneously, we can add the two equations to get 2x = 3218, which gives x = 1609. Substituting x back into the first equation, we find y = 2500 - 1609 = 891. Thus, the two numbers are 1609 and 891.
I think you have mistyped your question...
Well, isn't that just a happy little math problem! If we have two numbers that add up to 750 and have a difference of 162, we can solve this by setting up a system of equations. Let's call the smaller number x and the larger number y. So, we have x + y = 750 and y - x = 162. By solving these equations, we find that the two numbers are 294 and 456. Happy calculating!
6
Let the two numbers be ( x ) and ( y ). From the information given, we can set up the equations: ( x - y = 10 ) and ( x + y = 14 ). Solving these equations, we find that ( x = 12 ) and ( y = 2 ). Thus, the two numbers are 12 and 2.
To find the two numbers, we can use the fact that the LCM of two numbers is equal to the product of the two numbers divided by their greatest common divisor (GCD). Since the LCM is 60, and the difference of the two numbers is 3, we can set up a system of equations. Let the two numbers be x and y. We have xy/GCD(x,y) = 60 and x - y = 3. By solving these equations simultaneously, we can find the two numbers.
You can experiment with different numbers (trial-and-error). You can also write this as simultaneous equations: a + b = 50 (the sum of the two numbers is 50) a - b = 10 (the difference is 10) There are several approaches to simultaneous equations; in this case, it is easy to solve by adding the two equations together: a + b + a - b = 60 2a = 60 a = 30 So, the first number is 30. You can get the second number by replacing in any of the original equations.
To find two numbers that equal a sum of 7 and a difference of 1, let’s denote the numbers as ( x ) and ( y ). From the information given, we can set up the equations: ( x + y = 7 ) and ( x - y = 1 ). Solving these equations, we find that ( x = 4 ) and ( y = 3 ). Thus, the two numbers are 4 and 3.
This is a good exercise in building and solving a set of equations. Let X and Y be the two numbers. Then you are told their sum is 36, so write; X + Y = 36 Then you are told their difference is 24, so write; X - Y = 24 Now elliminate Y by adding the two equations; 2X = 60 and X = 30 . Now you can find Y by substituting this answer into either of the two original equations to get Y = 6.
Let's represent the two numbers as x and y. We can create a system of equations to solve for x and y: x + y = 5 (equation 1) x - y = 0.5 (equation 2) By solving this system of equations, we can find that the two numbers are 2.75 and 2.25.
To determine the two numbers, assume the numbers to be 'x' and 'y'. Now, given that the sum of the numbers is 40. Therefore, x + y = 40 --> (A) Also, given that the difference of the numbers is 10. Therefore, x - y = 10 --> (B) Add the equations (A) and (B): 2x = 50, which gives x = 25. Use any of the equations above to determine 'y'. Using equation A: 25 + y = 40, which gives y = 15. Therefore, the numbers are 25 and 15.