x + y = 50
x - y = 16
--------------- (add the two equations to solve for x)
2x = 66
x = 33
then substitute x into one of the above equations to get y = 17
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 8 ) and ( x - y = 4 ). Solving these two equations simultaneously, we can find ( x = 6 ) and ( y = 2 ). Thus, the two numbers are 6 and 2.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 17 ) and ( x - y = 7 ). By solving these equations, we find that ( x = 12 ) and ( y = 5 ). Thus, the two numbers are 12 and 5.
Let the two numbers be ( x ) and ( y ). According to the problem, their sum is given by ( x + y = 40 ) and their difference is ( x - y = 10 ). Solving these equations simultaneously, we find ( x = 25 ) and ( y = 15 ). Thus, the sum of the two numbers is 40.
Let the two numbers be ( x ) and ( y ). From the problem, we have the equations ( x + y = 17 ) and ( x - y = 2 ). Solving these simultaneously, we add the equations to get ( 2x = 19 ), which gives ( x = 9.5 ). Substituting ( x ) back into the first equation, ( y = 17 - 9.5 = 7.5 ). Thus, the two numbers are 9.5 and 7.5.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 18 ) and ( x - y = 2 ). Solving these equations, we add them to get ( 2x = 20 ), so ( x = 10 ). Substituting ( x ) back into the first equation, ( 10 + y = 18 ) gives ( y = 8 ). Thus, the two numbers are 10 and 8.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 8 ) and ( x - y = 4 ). Solving these two equations simultaneously, we can find ( x = 6 ) and ( y = 2 ). Thus, the two numbers are 6 and 2.
First, we need to clarify the condition in the problem: the sum of two numbers is 16, and the difference between the two numbers is 6. Based on these conditions, we can say that these two numbers are respectively x and y. According to the problem description, we can list the following equations: The sum of the two numbers is 16, which is x plus y is equal to 16. The difference between the two numbers is 6, which is 6 x−y=6. By solving this system of equations, we get x=9 and y=7. So the product of these two numbers is 9 x 7 = 63
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 17 ) and ( x - y = 7 ). By solving these equations, we find that ( x = 12 ) and ( y = 5 ). Thus, the two numbers are 12 and 5.
Let the two numbers be ( x ) and ( y ). According to the problem, their sum is given by ( x + y = 40 ) and their difference is ( x - y = 10 ). Solving these equations simultaneously, we find ( x = 25 ) and ( y = 15 ). Thus, the sum of the two numbers is 40.
Let the two numbers be ( x ) and ( y ). From the problem, we have the equations ( x + y = 17 ) and ( x - y = 2 ). Solving these simultaneously, we add the equations to get ( 2x = 19 ), which gives ( x = 9.5 ). Substituting ( x ) back into the first equation, ( y = 17 - 9.5 = 7.5 ). Thus, the two numbers are 9.5 and 7.5.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 18 ) and ( x - y = 2 ). Solving these equations, we add them to get ( 2x = 20 ), so ( x = 10 ). Substituting ( x ) back into the first equation, ( 10 + y = 18 ) gives ( y = 8 ). Thus, the two numbers are 10 and 8.
Let the two numbers be ( x ) and ( y ). From the problem, we have the equations ( x + y = 100 ) and ( x - y = 6 ). Solving these equations, we can add them to eliminate ( y ): ( 2x = 106 ), so ( x = 53 ). Substituting back, ( y = 100 - 53 = 47 ). Thus, the two numbers are 53 and 47.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 500 ) and ( x - y = 156 ). Solving these simultaneously, we can add the two equations to get ( 2x = 656 ), which gives ( x = 328 ). Substituting back, we find ( y = 500 - 328 = 172 ). Thus, the two numbers are 328 and 172.
Let the two numbers be ( x ) and ( y ). From the problem, we have the equations ( x + y = 43 ) and ( x - y = 9 ). Solving these simultaneously, we can add both equations to get ( 2x = 52 ), which means ( x = 26 ). Substituting ( x ) back into the first equation gives ( y = 17 ). Thus, the two numbers are 26 and 17.
Let the two numbers be x and y. According to the problem, we have the equations: x + y = 2500 and x - y = 718. Solving these simultaneously, we can add the two equations to get 2x = 3218, which gives x = 1609. Substituting x back into the first equation, we find y = 2500 - 1609 = 891. Thus, the two numbers are 1609 and 891.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 14 ) and ( x - y = 4 ). Solving these simultaneously, we can add the two equations to get ( 2x = 18 ), which gives ( x = 9 ). Substituting ( x ) back into the first equation, ( y = 14 - 9 = 5 ). Thus, the two numbers are 9 and 5.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 40 ) and ( x - y = 10 ). Solving these, we can add the two equations to find ( 2x = 50 ), giving ( x = 25 ). Substituting ( x ) back into the first equation, ( y = 40 - 25 = 15 ). Thus, the two numbers are 25 and 15.