x + y = 50
x - y = 16
--------------- (add the two equations to solve for x)
2x = 66
x = 33
then substitute x into one of the above equations to get y = 17
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 17 ) and ( x - y = 7 ). By solving these equations, we find that ( x = 12 ) and ( y = 5 ). Thus, the two numbers are 12 and 5.
Let the two numbers be ( x ) and ( y ). From the problem, we have the equations ( x + y = 17 ) and ( x - y = 2 ). Solving these simultaneously, we add the equations to get ( 2x = 19 ), which gives ( x = 9.5 ). Substituting ( x ) back into the first equation, ( y = 17 - 9.5 = 7.5 ). Thus, the two numbers are 9.5 and 7.5.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 18 ) and ( x - y = 2 ). Solving these equations, we add them to get ( 2x = 20 ), so ( x = 10 ). Substituting ( x ) back into the first equation, ( 10 + y = 18 ) gives ( y = 8 ). Thus, the two numbers are 10 and 8.
Let the two numbers be x and y. According to the problem, we have the equations: x + y = 2500 and x - y = 718. Solving these simultaneously, we can add the two equations to get 2x = 3218, which gives x = 1609. Substituting x back into the first equation, we find y = 2500 - 1609 = 891. Thus, the two numbers are 1609 and 891.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 14 ) and ( x - y = 4 ). Solving these simultaneously, we can add the two equations to get ( 2x = 18 ), which gives ( x = 9 ). Substituting ( x ) back into the first equation, ( y = 14 - 9 = 5 ). Thus, the two numbers are 9 and 5.
First, we need to clarify the condition in the problem: the sum of two numbers is 16, and the difference between the two numbers is 6. Based on these conditions, we can say that these two numbers are respectively x and y. According to the problem description, we can list the following equations: The sum of the two numbers is 16, which is x plus y is equal to 16. The difference between the two numbers is 6, which is 6 x−y=6. By solving this system of equations, we get x=9 and y=7. So the product of these two numbers is 9 x 7 = 63
Let the two numbers be ( x ) and ( y ). From the problem, we have the equations ( x + y = 17 ) and ( x - y = 2 ). Solving these simultaneously, we add the equations to get ( 2x = 19 ), which gives ( x = 9.5 ). Substituting ( x ) back into the first equation, ( y = 17 - 9.5 = 7.5 ). Thus, the two numbers are 9.5 and 7.5.
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 18 ) and ( x - y = 2 ). Solving these equations, we add them to get ( 2x = 20 ), so ( x = 10 ). Substituting ( x ) back into the first equation, ( 10 + y = 18 ) gives ( y = 8 ). Thus, the two numbers are 10 and 8.
Let the two numbers be x and y. According to the problem, we have the equations: x + y = 2500 and x - y = 718. Solving these simultaneously, we can add the two equations to get 2x = 3218, which gives x = 1609. Substituting x back into the first equation, we find y = 2500 - 1609 = 891. Thus, the two numbers are 1609 and 891.
I think you have mistyped your question...
Well, isn't that just a happy little math problem! If we have two numbers that add up to 750 and have a difference of 162, we can solve this by setting up a system of equations. Let's call the smaller number x and the larger number y. So, we have x + y = 750 and y - x = 162. By solving these equations, we find that the two numbers are 294 and 456. Happy calculating!
6
Let the two numbers be ( x ) and ( y ). According to the problem, we have the equations ( x + y = 40 ) and ( x - y = 10 ). Solving these simultaneously, we can add the two equations to get ( 2x = 50 ), which gives ( x = 25 ). Substituting ( x ) back into the first equation, we find ( y = 15 ). Therefore, the two numbers are 25 and 15.
Let the two numbers be ( x ) and ( y ). From the information given, we can set up the equations: ( x - y = 10 ) and ( x + y = 14 ). Solving these equations, we find that ( x = 12 ) and ( y = 2 ). Thus, the two numbers are 12 and 2.
To find the two numbers, we can use the fact that the LCM of two numbers is equal to the product of the two numbers divided by their greatest common divisor (GCD). Since the LCM is 60, and the difference of the two numbers is 3, we can set up a system of equations. Let the two numbers be x and y. We have xy/GCD(x,y) = 60 and x - y = 3. By solving these equations simultaneously, we can find the two numbers.
You can experiment with different numbers (trial-and-error). You can also write this as simultaneous equations: a + b = 50 (the sum of the two numbers is 50) a - b = 10 (the difference is 10) There are several approaches to simultaneous equations; in this case, it is easy to solve by adding the two equations together: a + b + a - b = 60 2a = 60 a = 30 So, the first number is 30. You can get the second number by replacing in any of the original equations.
To find two numbers that equal a sum of 7 and a difference of 1, let’s denote the numbers as ( x ) and ( y ). From the information given, we can set up the equations: ( x + y = 7 ) and ( x - y = 1 ). Solving these equations, we find that ( x = 4 ) and ( y = 3 ). Thus, the two numbers are 4 and 3.