If the equation is 4x squared - 5x + 10 = 0, then you set a = 4, b = -5, c = 10. Replace these numbers in the quadratic formula.
Doesn't factor evenly, use quadratic
You just plug in the coefficients, and do the normal operations. Of course you have to know how to calculate with complex numbers. Assuming the coefficients are real, you may at some moment get the root of a negative number. Say, for instance, you have the square root of minus 2, then the solution of that part is the square root of plus 2, multiplied by i.If the original coefficients are complex, you may have to calculate the root of a complex number. This is a little more complicated. For this, you convert the complex number to polar coordinates - that is, to a length and an angle. Then, to actually take the square root, you take half the angle, and the square root of the distance - and convert back to rectangular coordinates (separating the real and the imaginary part). (For the second solution, add 180 degrees to the angle.)
you have to use F.O.I.L method to simplify it.
Let x = first positive integer the x + 1 is the next positive integer the product is x (x+1) = 210 x^2 + x = 210 x^2 + x - 210 = 0 Use quadratic equation to solve, or factor (X+15) (X-14 ) = 0 x = +14 or X = -15 The positve one is x = 14 X + 1 = 15 ANS: 14 and 15
let x = 1st number, then 19 - x = 2nd number 120 = x(19 - x) x2 -19x +120 = 0 use quadratic formula to solve x = (19 +/- sq rt(361 - 480))/2 x = (19 + sq root (-119))/2 or x = (19 - sq root (-119))/2 '''x = 19/2 + ''i''(sq rt 119) /2 and''' '''x = 19/2 - ''i''(sq rt 119) /2''' there are no real solutions, both are imaginary. Actually they are complex conjugates.
Use the quadratic formula. x = -4.265564 or -0.234436
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.
If you can't factor it easily, use the quadratic formula.
If you can't factor it easily, use the quadratic formula.
Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.
All you do is set the quadratic function to equal to 0. Then you can either factor or use the quadratic formula to solve for your unknown variable.
The Quadratic formula in mathematics is used to solve quadratic equations in algebra. The simplest way to solve these equations is to set each of the factors to zero and then solve each factor separately.
6t2+25+11 = (3t+11)(2t+1) when factored Use the quadratic equation formula.
Because it's part of the quadratic equation formula in finding the roots of a quadratic equation.
You convert the equation to the form: ax2 + bx + c = 0, replace the numeric values (a, b, c) in the quadratic formula, and calculate.
A quadratic function is ax2+bx+c You can solve for x by using the quadratic formula, which, as the formula requires the use of square roots, would be tricky to put here.
I suggest you use the quadratic formula, with a = 3, b = -2, c = 7.