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How can you solve the problem finding two consecutive positive integers whose product is 210?
Let x = first positive integer
the x + 1 is the next positive integer
the product is
x (x+1) = 210
x^2 + x = 210
x^2 + x - 210 = 0
Use quadratic equation to solve, or factor
(X+15) (X-14 ) = 0
x = +14 or X = -15
The positve one is x = 14
X + 1 = 15
ANS: 14 and 15
What else can I help you with?
How are multiplying integers and dividing integers same?
following multiplication integer rules and division rules, you should get: "MULTIPLICATION: minus times minus is plus (negative x negative = positive).....minus times plus is minus (negative x positive = negative).....plus times plus is plus (positive x positive = positive) DIVISION: minus divi minus is plus (negative ÷ negative = positive)......minus divi plus is minus (negative ÷ positive = negative).....plus divi plus is plus (positive ÷ positive = positive)" a division problem is a multiplication problem in disguise
What are two consecutive integers whose sum is 45?
Well, honey, if you're looking for a pair of consecutive integers that add up to 45, then it's simple math. Just take 22 and 23. Those two bad boys will give you a total of 45. So there you have it, now go impress someone with your newfound integer knowledge.
What is the rule for subtracting integers?
if they are two positive numbers, do it normally.If there is a negative and a positive, change it to addition and switch the SECOND integer sign. Only works with two integers in a subtraction question.Example: (-32)-(+2)= (-34) / (-32)+(-2)=(-34)
Which equation should be used to solve this problem The sum of two consecutive even integers is 42 Find the numbers?
2x + 2 = 42 x = 20 20 and 22
How do you add integers?
To add integers there are few rules. if your adding a negative and a negative, the answer is always negative!-5 + -5= -10 Examples:-6 + -2 = -8-10 + -10 =-20-2 + -5 = -7When your adding a positive and a negative... well it depends. A positive and a negative are opposites: so they cancel each other out. In other words, when adding a positive and a negative, go to the right of the number line.Examples:-8 + 3 = -5-1 + 5 = 46 + -2 = 8Theres also another way to do it. Forget the signs! Take the greater number (positive and negative) and put it on the top. Then make a subtraction problem.-10 + 6 =10 - 6 = 4Which number is greater? that's right, ten! 10 was origanally a negative so your answer is negative.Answer -4
The number 21 is the sum of two consecutive integers 10 and 11. What is the largest number of positive consecutive integers whose sum is 21?
For this particular problem, you just need to experiment a little. 1 + 2 + 3 + 4 + 5 +6 = 21 (6 integers).
What is a problem that the sum of three consecutive odd integers is 45?
13+15+17=45
How do you solve this problem find two consecutive odd integers whose sum is 20?
9 and 11
What are two consecutive integers that is equal to 48?
There are no two consecutive integers which sum to make 48. The closest you can get is if you drop the integer part of the problem and state simply that they have to have a difference of 1 between them. In which case it would be 23.5 and 24.5.
What are three consecutive integers sum is 125?
Let the three consecutive integers be n, n+1, and n+2. The sum of these integers is n + (n+1) + (n+2) = 3n + 3 = 125. Therefore, 3n = 122 and n = 122/3 = 40.67. Since n must be an integer, the consecutive integers are 40, 41, and 42.
Find four consecutive odd integers if the product of the smaller two is 112 less than the larger two?
The first 4 consecutive integers can be written as the following:XX+1X+2X+3From the problem the we get the following equation:2*(X)*(X+3) - {(X)*(X+3)} = 42X2+6X - X2 - 3X = 4X2 + 3X - 4 = 0Factoring this quadratic equation is (X+4)(X-1) = 0So the 1st positive integer is X-1 = 0 or X=1and the other integers is 2,3,4----Comment by Kirbysuper----But... those integers aren't positive numbers... in the question, it says to find 4 consecutive positiveintegers.
Solve for x x over 4 - 5 over 8 equals x plus 316?
Find two consecuitive integers whose sum is 89. To solve this problem, let x be the smaller of these integers. What is the larger of these two consecutive integers? In terms of x, write a formula that represents the sum of these two consecutive integers.
Three consecutive integers that have the sum of 96?
If three consecutive integers have the sum of 96, then the problem can be expressed with the equation... N + (N+1) + (N+2) = 96 ...Simplify that and solve and you get... 3N + 3 = 96 3N = 93 N = 31 ... so the three integers are 31, 32, and 33.
How can you solve the problem of finding 4 consecutive integers whose sum is 94?
Since consecutive integers differ by one, let's represent them as x, x + 1, x + 2, and x + 3. So we have, x + (x + 1) + (x + 2) + (x + 3) = 94 4x + 6 = 94 4x = 88 x = 22 Thus, the numbers are 22, 23, 24, and 25. (Check:)
Find the integers if the product of two consecutive even integers is 168?
Call the smaller of the two consecutive integers n. Then, from the problem statement: n(n+2) = 168, or n2 + 2n - 168 = 0, or (n + 14)(n - 12) = 0, which is true when n = -14 or +12. Therefore, the two integers sought are 12 and 14.
How do you setup a consecutive integer problem?
the first number is x, the second x+1, third, x+2 and so on.so if the sum of three consecutive integers is 24, the setup would be this:x+x+1+x+2=24if it's consecutive even or odd integers the setup would be x, x+2, x+4,etc.so if the sum of three consecutive odd integers is 21, the setup would be:x+x+2+x+4=21for three or more even consecutive numbers, same setup
What are four consecutive even integers whose sum is 244?
Call the lowest of the even integers n. Then from the problem statement, n + n + 2 + n + 4 = n + 6 =244. Collecting like terms results in 4n + 12 = 244, or 4n = 244 - 12 = 232, or n = 232/4 or 58. The consecutive even integers are therefore, 58, 60, 62, and 64.
