This will pull 20 Amps continuous so you will need a 30 A breaker and 10 AWG wire. You would have Black, Red, White and Ground. The 240 V would be on the black and red connected to the output from a two pole 240 A breaker. White would be neutral and green or bare wire would be ground.
Yes but you will not get the full watt rating out of the tank. Watts = amps x volts. Say the tank draws 20 amps. 20A x 240V = 4800 watts. 20A x 208V = 4160 watts. It will take longer to heat your water with less wattage.
Watts = Current x Volts with your resistive heat application. To figure out resistance you need to know voltage and current. Since you are drawing 6 amps then Volts = 325/6. This means that there is about 54 volts supplying the heater which seems like a very strange supply voltage. Since Volts = Current x Resistance the resistance = 325/36.
about 4800 watt but should not use it 100% so to be safe 4000 watt (80%)
120 volts.
Each baseboard heater will draw a little over 4 amps at 120 volts or 2 Amps at 240 volts. The total number of baseboards on a circuit will draw the sum of these amps. Keep the load under 80% of the amperage rating of the breaker.
Yes. watts / volts = amps. 4800/240=20amps.
Current in amps = watts/ voltage in volts. If you have a 240 volt supply, it will draw 4800/240 = 20 amps, so no. This is a very powerful water heater, and would normally be wired into a dedicated circuit, presumably with a 30 amp breaker.
Yes, a 1500 watt heater operating on 120 volts has an amperage of A = W/V. Amps = Watts/Volts = 1500/120 = 12.5 amps. It is not a recommended practice to do so.
Watts = Amps x Volts for a resistive load like a water heater.
Yes but you will not get the full watt rating out of the tank. Watts = amps x volts. Say the tank draws 20 amps. 20A x 240V = 4800 watts. 20A x 208V = 4160 watts. It will take longer to heat your water with less wattage.
The formula you are looking for is I = W/E.
Watt volts is not an electrical term. Watts are the product of amps times volts.
10 Amps. Amps=Watts/Volts
That depends on circuit voltage. 1 watt is equal to 1 volt times 1 amp.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
The load is a resistive load and as such it is governed by Ohm's law. Current is directly proportional to the voltage and inversely proportional to the resistance. As the voltage goes down so does the current. 2200 watt heater at 220 volts = 10 amps. R = E/I = 220/10 = 22 ohms of resistance in the heater. Now take the 2200 watt heater and using the same formula and at 110 volts. I = E/R, Amps = Volts / Resistance. 110/22 = 5 amps. As you can see ohm's law holds true, the current is inversely proportional to the resistance and as the voltage goes down so does the current. To answer the question, yes a 220 volt heater will run on a 110 volt circuit but at a reduced wattage. W = A x V = 5 x 110 = 550 watts.A 2200 watt heater at 220 volts would draw 1/2 the current of a 2200 watt heater at 110 volts.A 2200 watt heater at 220 volts is 22 ohms of resistance. Resistance would not change with the voltage, current would only be 5 amps (a resistor is a current limiter, it will only let more current through if you apply more voltage not less); but the wattage would only be 550 watts. This would only give you a fourth of the power this heater was designed for! The heater and the wires would have less heat.
It will not work. It will work, but you will only receive 25% of the rated output of the tank. A 3000 watt heater will only product 750 watts at 110 volts.