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First find the midpoint of the line segment AB which is: (-2, 3)

Then find the slope of AB which is: -5/2

The slope of the perpendicular bisector is the positive reciprocal of -5/2 which is 2/5

Then by using the straight line formula of y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:-

y-3 = 2/5(x-(-2))

y = 2/5x+4/5+3

y = 2/5x+19/5 => 5y = 2x+19

So the equation for the perpendicular bisector can be expressed in the form of:-

2x-5y+19 = 0

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Q: How do you work out an equation for the perpendicular bisector of the line segment AB when A is at -4 8 and B is at 0 -2?
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