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The sum of the interior angles of a polygon of n sides is 180o * (n-2).

For a regular nonagon (9 sides), the sum is (9 - 2) * 180o = 1260o, so each interior angle is 1260o / 9 = 140o.

The exterior angle is the supplement of the interior angle: 180o - 140o = 40o.

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Q: How do you work out internal and external angles of a regular nonogon?
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