2x + 5y = 8
4x - 3y = 3
You are working with a system of equations, containing 2 variables. There is no need to use a matrix nor any complex method, just simple elimination:
2(2x + 5y) = 2(8) = 16
4x - 3y = 3
4x + 10y = 16
4x - 3y = 3
Subtract both equations:
13y = 13
Divide by 13:
y = 1
Plug it back into the original equation:
2x + 5(1) = 8
2x = 8 - 5 = 3
x = 3/2 = 1.5.
Therefore, your ordered pair is: (1.5, 1).
4x3y
it's 5
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2.
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
x4y3Answer BIt can be written as x4y3 but it can be switched around such as:4x3y. This means 4 lots of x's and 3 lots of y's or 4x times 3y.Ermm I could be wrong.