Arthur Pythagoras: Diagonal = sqrt (square of side 1 + square of side 2)
In your case D = sqrt (2 x 2500) = 70.71cm
Addendum: If it is a square, as is your case, multiply the length of one side by the square root of 2:
1.4142 * 50.00 cm = 70.71 cm.
(Arthur?)
Pythagoras! If AB = 100m and BC = 75cm then AC = sqrt (10000 + 5625) = 125
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
Two equal size right angle triangles.
50cm - 20cm roughly, why do you want to know this anyway?
d = 11.5 inches.
Pythagoras! If AB = 100m and BC = 75cm then AC = sqrt (10000 + 5625) = 125
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
Two equal size right angle triangles.
small= 70cm by 50cm med= 90cm by 50cm large= 1m by 67cm. I hope they are the answers you were looking for.
squares or more rectangles depending on the size of the rectangle to begin with and how you cut it.
50cm - 20cm roughly, why do you want to know this anyway?
13 cm Solved with the help of the quadratic formula and Pythagoras' theorem.
diagonal
A meerkat can weigh about 2 pounds and are 20cm to 50cm including their tail.
4 tiles.4 tiles.4 tiles.4 tiles.