Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal.
Here, a = 5 [cm] and b = 10 [cm]
So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored)
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Pythagoras! If AB = 100m and BC = 75cm then AC = sqrt (10000 + 5625) = 125
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
Two equal size right angle triangles.
Arthur Pythagoras: Diagonal = sqrt (square of side 1 + square of side 2) In your case D = sqrt (2 x 2500) = 70.71cm Addendum: If it is a square, as is your case, multiply the length of one side by the square root of 2: 1.4142 * 50.00 cm = 70.71 cm. (Arthur?)
The length of the diagonal is 208.7*sqrt(2) = 295.1 ft.
d = 11.5 inches.
Pythagoras! If AB = 100m and BC = 75cm then AC = sqrt (10000 + 5625) = 125
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
Two equal size right angle triangles.
10cm
Arthur Pythagoras: Diagonal = sqrt (square of side 1 + square of side 2) In your case D = sqrt (2 x 2500) = 70.71cm Addendum: If it is a square, as is your case, multiply the length of one side by the square root of 2: 1.4142 * 50.00 cm = 70.71 cm. (Arthur?)
the size is 10cm
squares or more rectangles depending on the size of the rectangle to begin with and how you cut it.
13 cm Solved with the help of the quadratic formula and Pythagoras' theorem.
10cm to 15cm
10cm
diagonal