Volume = pi*radius2*height
A cylindrical paint can has a diameter of 12 centimeters and a height of 16 centimeters. Which isclosestto the volume of the paint can in cubic centimeters?
Work out its radius by 0.5/2*pi and use the volume formula: pi*radius^2*height. It should work out to about 0.006 cubic m.
Assuming the paint tin is cylindrical, then the surface area of the cylinder would be the two circles (the top and bottom of the tin) and the circumference of the circle x the height of the cylinder. Think about like this, if you cut open the tin and unfold it, you will get two circles and a rectangle. The side lengths of the rectangle are the height of the cylinder and the circumference of the circle. So the equation should look like this: 2*pi*r2+h*2*pi*r where r is the radius of the top of the paint tin, and h is the height of the paint tin.
Since the diameter is 10cm, the radius is 5cm. The area of the base is 25*pi square cm. We must multiply that base value by the height, which makes 625pi cubic cm.
The amount of paint needed is a function of the radius
That could be calculated if we knew the height of the can. It can't be calculated if we only know the capacity. If we can make the height anything we want, we can build an infinite number of 2.5-litre cans that all have different radii.
A cylinder 5 meters by 5 meters has a surface area of 25 square meters. If the paint is 1 micron thick, that equals 0.000001 meters. so the volume would be 25 x 0.000001 = 0.000025 cubic meters
First off, let's clear up area and volume. Area is for two dimensional shapes, like squares and circles. Volume is for three dimensional shapes like cubes and spheres. The area of a cone would be the area of the ellipse at the base of the cone (the circle) plus the area of the pointy bit, when it's unrolled. This would be like the area you would need to paint if you painted the outside. Assuming that the base of the cone is a circle, then the area of the base is: pi * radius * radius (pies are square) The area of the pointy bit is: pi * radius * S, where S is the length of the slope from a point on to the circle to the tip (hypotenuse). Add the two together to get the total area = ( pi * r * S ) + ( pi * r * r ) Now the S length is really derived from the height of the cone (from the center of the circle to the point) and radius of the base circle. Remember Pythagoras, S = square root of ( ( h * h ) + ( r * r ) ) Well, if you are actually looking for the volume (how much water it takes to fill up the cone), then you need: volume = 1/3 * pi * radius * radius * height
2.6667 litres
pi*r squared*h pi*5 squared*12 pi*25*12 942!
Any height. The size you have has the base about that of a tin of paint. But it could be any height.
The answer is 6.6