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9 < y
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If: 3y-7 = 2y+9 Then: 3y-2y = 9+7 So: y = 16
9>y≥5
Absolute value of (y - x) is equal to or less than 9 . |y-x| ≤ 9
Write an expression for "7 less than y."
y - 9
y < 6
y < 10.
10 < y
6<y²
It is: 8 > Y > -2
y subtracted by 6 6 less than y
15 less than y the difference of 15 and y