4y
5x-15y = -10
15y^8 - 7y^3 = y^3(15y^5 - 7)
15y+14=2(5y+6) 15y+14=10y+12 15y+14-14=10y+12-14 15y=10y-2 15y-10y=10y-2-10y 5y=-2 y=-2/5
x/5y + 2x/3y = 3x/15y + 10x/15y = 13x/15y
It is two terms of an algebraic expression in the form of: x-15y
4y
5x-15y = -10
be and been
run write
GCF(15y, 25) = 5.
3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20
write the product of 117 two different ways
write two ways to name one year
15y^8 - 7y^3 = y^3(15y^5 - 7)
15y+14=2(5y+6) 15y+14=10y+12 15y+14-14=10y+12-14 15y=10y-2 15y-10y=10y-2-10y 5y=-2 y=-2/5
two hundred