The standard form of a polynomial of degree (order) n isa(n)*x^n + a(n-1)*x^(n-1) + ... + a(1)*x + a(0).
Normally, of course, a(k) would be written as "a-suffix k" and x^k as "x-superscript k" which makes the whole thing look neater but, for reasons that I cannot fathom, this browser cannot handle superscripts nor subscripts.
That already is a polynomial in standard form.
Terms
Powers of their exponents
The standard form of a polynomial of degree n is anxn + an-1xn-1 + ... + a1x + a0 where the ai are constants.
A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.
The polynomial is (x + 1)*(x + 1)*(x - 1) = x3 + x2 - x - 1
Standard Form
Polynomial fuction in standard form with the given zeros
As a polynomial in standard form, x plus 5x plus 2 is 6x + 2.
2x is just 2x and it is not a polynomial. This is a monomial because it just has one term. a polynomial is four or more terms.
-5x + 729
How do write 666 in standard form?