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What is a cubic polynomial function in standard form with zeros -4-5 and 5?
x3 + 4x2 - 25x - 100 = 0
How do you write 466x as a polynomial in standered form?
That already is a polynomial in standard form.
What is a cubic polynomial function in standard form with zeros 1 -2 and 2?
It is x^3 - x^2 - 4x + 4 = 0
What is the standard form for a polynomial?
The standard form of a polynomial of degree n is anxn + an-1xn-1 + ... + a1x + a0 where the ai are constants.
Write a polynomial degree with real coefficients whose zeros include 13 plus i and 2 Write the polynomial degree in standard form?
To have a zero at 2, you need to include a factor (x - 2). To have a zero at 13 + i, you need a factor (x - (13 + i)). To have real coefficients, for each non-real factor you need to include its complex conjugate, so in this case, (x + 13 + i).Thus, you have the factors: (x - 2)(x - (13 + i))(x + 13 + i) You can multiply the factors together to get the polynomial into standard form. I suggest you start with the complex conjugates, that makes it easier.
What is The equation of a rational function does not have to contain a rational expression?
A rational function is defined as a function that can be expressed as the quotient of two polynomials. However, it can also be represented in forms that do not explicitly show a rational expression, such as a polynomial or a constant function, which can be thought of as a rational function with a denominator of 1. For example, the function ( f(x) = 3x^2 + 2 ) is a polynomial and can be considered a rational function because it can be rewritten as ( f(x) = \frac{3x^2 + 2}{1} ). Thus, while the standard form includes a rational expression, the definition encompasses more than just explicit fractions.
Is x over 3 a polynomial?
No, ( \frac{x}{3} ) is not considered a polynomial because it is expressed as a rational expression. However, if you rewrite it as ( \frac{1}{3}x ), it is a polynomial of degree 1, since it can be expressed in the standard form ( ax^n ), where ( a = \frac{1}{3} ) and ( n = 1 ). Polynomials can include constants, whole number coefficients, and non-negative integer exponents only.
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 2 -4 and 1 plus 3i?
To write a polynomial function with real coefficients given the zeros 2, -4, and (1 + 3i), we must also include the conjugate of the complex zero, which is (1 - 3i). The polynomial can be expressed as (f(x) = (x - 2)(x + 4)(x - (1 + 3i))(x - (1 - 3i))). Simplifying the complex roots, we have ((x - (1 + 3i))(x - (1 - 3i)) = (x - 1)^2 + 9). Thus, the polynomial in standard form is: [ f(x) = (x - 2)(x + 4)((x - 1)^2 + 9). ] Expanding this gives the polynomial (f(x) = (x - 2)(x + 4)(x^2 - 2x + 10)), which can be further simplified to the standard form.
How do I write an equation in standard form with integer coefficients?
The answer will depend on the form of the equation. Whether it is an equation in one or more variables, whether it is linear or polynomial, there are different standard forms for exponential equations.
What is a cubic polynomial function in standard form with zeros -4-5 and 5?
x3 + 4x2 - 25x - 100 = 0
How do you write 466x as a polynomial in standered form?
That already is a polynomial in standard form.
What is a cubic polynomial function in standard form with zeros 1 -2 and 2?
It is x^3 - x^2 - 4x + 4 = 0
What is the standard form for a polynomial?
The standard form of a polynomial of degree n is anxn + an-1xn-1 + ... + a1x + a0 where the ai are constants.
Why is it vietor triangle is inverted?
The Vieta triangle is inverted to provide a geometric interpretation of Vieta's formulas in relation to the roots of a polynomial. By inverting the triangle, the relationships between the roots and the coefficients of the polynomial can be visually represented, allowing for easier understanding of how the roots interact. This inversion can also highlight symmetries and relationships that might not be as apparent in a standard orientation.
Write a polynomial degree with real coefficients whose zeros include 13 plus i and 2 Write the polynomial degree in standard form?
To have a zero at 2, you need to include a factor (x - 2). To have a zero at 13 + i, you need a factor (x - (13 + i)). To have real coefficients, for each non-real factor you need to include its complex conjugate, so in this case, (x + 13 + i).Thus, you have the factors: (x - 2)(x - (13 + i))(x + 13 + i) You can multiply the factors together to get the polynomial into standard form. I suggest you start with the complex conjugates, that makes it easier.
What is the polynomial of 2x in standard form?
2x is just 2x and it is not a polynomial. This is a monomial because it just has one term. a polynomial is four or more terms.
How do you rewrite an polynomial and standard form?
A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.A polynomial, of degree n, in standard form is:anxn + an-1xn-1 + ... + a1x+ a0 = 0 where n is an integer and the ai are constants.The answer about how to rewrite a polynomial depends on the form that it is given in.
