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This could have been an intriguing little exercise if you hadn't left the fraction out of the question. (If the fraction was supposed to be 1/2 then the answer is "No change".)
The question is not clear about how many of the three dimensions of the box are quadruples. For example, you could quadruple its height but leave the length and breadth unchanged.However, if you assume that all three dimensions are quadrupled, the surface area is 16 times as large and the volume is 64 times as great.
you can easely calculate it: the original measurements: 6(bottom)*6(height)*½=18 double the base half the height: 12*3*½=18 so it remains the same
Yes.
It must be made a third of its current value, ie divided by 3. The volume of a pyramid is 1/3 x area_base x height. The 1/3 is constant; to keep the volume constant as the base_area changes, the height must vary inversely. If the base_area is tripled, ie multiplied by 3, the height must be reduced to a third, ie divided by 3.
It is quadrupled.
quadrupled. :)
The area of the parallelogram is quadrupled.
This could have been an intriguing little exercise if you hadn't left the fraction out of the question. (If the fraction was supposed to be 1/2 then the answer is "No change".)
Its area is now eight times greater than its original size. If area = L x H, then 2(L) x (4)H = 8 (original area)
The area of the parallelogram is quadrupled.
The height to which a dropped ball rebounds is typically significantly greater than the height of the ball. Also, incidentally, the height of the ball usually doesn't change during the event, and remains equal to its original height.
It is quadrupled. volume_cylinder = π x radius2 x height If radius → 2 x radius then: new_volume = π x (2 x radius)2 x height = π x 22 x radius2 x height = 4 x π x radius2 x height = 4 x original_volume
As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.
The original Polly pocket dolls are about a centimeter in height. The newer Polly pocket dolls ( the ones where you can change their clothes) are about three inches in height
The question is not clear about how many of the three dimensions of the box are quadruples. For example, you could quadruple its height but leave the length and breadth unchanged.However, if you assume that all three dimensions are quadrupled, the surface area is 16 times as large and the volume is 64 times as great.
you can easely calculate it: the original measurements: 6(bottom)*6(height)*½=18 double the base half the height: 12*3*½=18 so it remains the same