Its area is now eight times greater than its original size.
If area = L x H, then 2(L) x (4)H = 8 (original area)
A rectangle is a good, simple shape to begin with. The area of a rectangle is equal to the product of the length of its base and the length of its height. The height is a segment that is perpendicular to the base. For a rectangle, the base and height are often called the "length" and the "width", and sometimes the height is referred to as the "altitude."
The volume is doubled.
If the radius and height of a cylinder are both doubled, then its surface area becomes 4 times what it was originally, and its volume becomes 8 times as much.
The volume of a circular cylinder varies directly with the height of the cylinder and with the square of the cylinder's radius If the height is halved and the radius is doubled then the volume will be increased.
Height = (Perimeter/2) - Base
quadrupled. :)
It is quadrupled.
As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.
increase
The area is multiplied by 4, not doubled.
It will be the same.
since the volume of a right cylinder is height x area of base, the area of the baseis Pi * r^2 (r is radius which is 1/2 of diameter), so the area of the base did notchange, while the height is doubled so the volume is doubled.
The area of the parallelogram is quadrupled.
The volume will be doubled.
The base areas quadruple and the curved surface doubles.
It is quadrupled. volume_cylinder = π x radius2 x height If radius → 2 x radius then: new_volume = π x (2 x radius)2 x height = π x 22 x radius2 x height = 4 x π x radius2 x height = 4 x original_volume
The area of the parallelogram is quadrupled.