They are equal.
yes
Length times Width times Height. Archimedes used a "bathtub", and submerged the object to see what volume of water was displaced.
I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.
Derive from measurements of length, breadth, height, radius, diameter etc. Measure the volume of displaced liquid when the object is submerged. If the object is of a material of known density (or specific gravity), weigh it and calculate volume from volume = mass/density.
the weight of the displaced water is equal to the weight of the object
Those volumes are equal.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
They are equal.
The buoyant force on a fully submerged object is equal to the weight of the water displaced. In fact, that's also true of a floating object.
They're equal.
The volume of the submerged object.
The magnitude of both forces is the same.
the object's volume
VOLUME :)
volume
yes
Displaced.