Q: The volume of a submerged object is equal to of the liquid displaced?

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I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.

They are equal.

Derive from measurements of length, breadth, height, radius, diameter etc. Measure the volume of displaced liquid when the object is submerged. If the object is of a material of known density (or specific gravity), weigh it and calculate volume from volume = mass/density.

Length times Width times Height. Archimedes used a "bathtub", and submerged the object to see what volume of water was displaced.

If the object is irregular you have no hope of calculating its volume from any known dimensions. The easiest way to find its volume is to fill a container full of a liquid (with which the object will not react). Submerge the object in the liquid and collect the liquid displaced. The volume of the displaced liquid, which should be easily measurable, will be the same as that of the object.

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Volume of liquid displaced = Volume of object submerged

The volume of the submerged object.

the object's volume

The buoyant force on an object in a liquid or gas has the same magnitude and the opposite direction of the weight of the liquid or gas displaced by the object. So basically, all you need to know is the weight of the displaced gas or liquid and the direction of gravity. The weight of the displaced gas or liquid can be derived from the density of the gas or liquid, the volume displaced, and the gravitational acceleration (weight = mass x gravity, and mass = density x volume). If the object is completely submerged, the volume of displaced liquid or gas is the same as the volume of the object minus the volume of the liquid or gas that enters the object (if the object is, for example, a sponge or a submarine with holes in it).

I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.

VOLUME :)

volume

They are equal.

I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.

They're equal.

a submerged object displaces liquid which is equal to its volume

A submerged object will displace its own volume of the liquid it is submerged in.