if the object is falling straight then the force from which the ball is falling toward earth is the gravitational force of the earth that is 9.81 m/sec2.
so by formula we have,
speed=distance/time ,also distance=speed*time
here if the ball is freely falling that is no external force is applied on ball then the s=gravitational pull and time given is 2 sec
there for in 2 sec the object fall ;
d=9.8 m/sec2 *2 sec
d=18.36 m(approx)
if any other suggestion then do tell me
I am no expert but I do believe the correct formula to use for this situation is d=1/2 gt2.
The formula above will only work for example if you are traveling at a constant velocity in a car of 9.8 meters per second. You need to take into account that an object in free fall is constantly accelerating and not in a constant motion.
The correct answer should be closer to 19.6 m.
320 meters
IF the object begins from rest, then it travels 1.5 x 10^8 meters. (rounded)
It works like this:10 meters / 3.09 seconds * 30 seconds / half minute = 97.09 meters / half-minute
(4 meters/second)(40 seconds) = 160 meters.
1.166 meters per sec.
78.46 meters (257.4 feet)
Ignoring air resistance, it would be 706 meters .
576 feet
320 meters
It has been known since the 16th century that the mass of an object is irrelevant to how far it will fall. The main factor influencing the rate of fall is the shape of the object and, therefore, the air resistance (or buoyancy).
122.5 meters (402.5 feet)
490 meters
4.9 meters (16.1 feet)
IF the object begins from rest, then it travels 1.5 x 10^8 meters. (rounded)
(25 meters per second) x (1.5 seconds) = 37.5 meters
Assuming the object is falling near the surface of the Earth and neglecting air resistance, the object will fall approximately 4.9 meters in 1 second. This calculation is based on the acceleration due to gravity, which is approximately 9.8 meters per second squared.
It works like this:10 meters / 3.09 seconds * 30 seconds / half minute = 97.09 meters / half-minute