if the object is falling straight then the force from which the ball is falling toward earth is the gravitational force of the earth that is 9.81 m/sec2.
so by formula we have,
speed=distance/time ,also distance=speed*time
here if the ball is freely falling that is no external force is applied on ball then the s=gravitational pull and time given is 2 sec
there for in 2 sec the object fall ;
d=9.8 m/sec2 *2 sec
d=18.36 m(approx)
if any other suggestion then do tell me
I am no expert but I do believe the correct formula to use for this situation is d=1/2 gt2.
The formula above will only work for example if you are traveling at a constant velocity in a car of 9.8 meters per second. You need to take into account that an object in free fall is constantly accelerating and not in a constant motion.
The correct answer should be closer to 19.6 m.
320 meters
IF the object begins from rest, then it travels 1.5 x 10^8 meters. (rounded)
It works like this:10 meters / 3.09 seconds * 30 seconds / half minute = 97.09 meters / half-minute
(4 meters/second)(40 seconds) = 160 meters.
1.166 meters per sec.
The final velocity of an object in free-fall after 2.6 seconds is approximately 25.48 m/s. The distance the object will fall during this time is approximately 33 meters.
An object in free fall will fall approximately 64 feet in 2 seconds.
Assuming the object is falling under gravity, it will fall approximately 78.4 meters in 4 seconds. This is based on the formula: distance = 0.5 x acceleration due to gravity x time squared.
Ignoring air resistance, it would be 706 meters .
Assuming the object starts from rest, the distance an object falls in 0.25 seconds can be calculated using the equation ( d = \frac{1}{2}gt^2 ), where (d) is the distance, (g) is the acceleration due to gravity (9.8 m/sĀ²), and (t) is the time. Substituting the values, the object would fall approximately 0.31 meters in 0.25 seconds.
Assuming the object is in free fall near Earth's surface, it will fall approximately 343.3 meters (1126 feet) in 7 seconds. This calculation is based on the formula for free fall distance: d = 1/2 * g * t^2, where d is the distance fallen, g is the acceleration due to gravity, and t is the time in seconds.
The object will move a total distance of 80 meters, which is calculated by multiplying the speed (10 m/s) by the time (8 seconds).
320 meters
It has been known since the 16th century that the mass of an object is irrelevant to how far it will fall. The main factor influencing the rate of fall is the shape of the object and, therefore, the air resistance (or buoyancy).
122.5 meters (402.5 feet)
An object dropped from near the Earth's surface will fall approximately 4.9 meters (16 feet) in the first second due to the acceleration of gravity. This distance is calculated using the formula s = 0.5 * g * t^2, where s is the distance, g is the acceleration due to gravity (9.8 m/s^2), and t is the time in seconds.
IF the object begins from rest, then it travels 1.5 x 10^8 meters. (rounded)