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Q: How high is a tree that's casts a ft shadow at the same time a ft pole casts a shadow which is ft long?

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50 feet

40 ft

5.5/8 = x/20 x=5.5*20/8 = 13.75 feet

17.45 feet.

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50 feet

40 ft

To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.

3.4

The shadow:object ratio is 1:1 so the tree is 63 feet high.

Not enough information has been given to solve this problem such as: What is the angle of elevation?

If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.

5.5/8 = x/20 x=5.5*20/8 = 13.75 feet

17.45 feet.

It is approx 36.6 ft.

(12 / 5) × 33 = 79.2 feet high Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2

28 feet