(12 / 5) × 33 = 79.2 feet high
Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet
Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
It is 90 feet in height
It is nearly 40 feet
Using Pythagoras' theorem it is 30 feet
The flagpole is 26 feet, 3 inches tall. (210/8 feet = 26.25 feet)Since the ratio of height to shadow is 6/8, the flagpole is also 3/4 as tall as its shadow.6/8 (man) = x/35 (pole)6/8 (35) = x210/8 = xx = 26.25 feet
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
The shadow:object ratio is 1:1 so the tree is 63 feet high.
The height of the tree is in direct proportion to the pole and its shadow
40 meters
17.45 feet.
15 feet high
It is 90 feet in height
It works out as 12 feet and 4 inches in height
6 feet
25 feet tall
3
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