28 feet
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
21 ft how is the equation to give you this result
The flagpole is 26 feet, 3 inches tall. (210/8 feet = 26.25 feet)Since the ratio of height to shadow is 6/8, the flagpole is also 3/4 as tall as its shadow.6/8 (man) = x/35 (pole)6/8 (35) = x210/8 = xx = 26.25 feet
It is nearly 40 feet
The flagpole is 14 feet tall - all of the shadows (at that particular time of day) are twice the length of the object. You can compare any values at that time, and the ratios are the same: x/ 28 = 4/8 (= 1/2) x = 14
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
Ten is to two as 40 is to x, yielding: 200ft.
It works out as: 42.353 feet tall rounded to 3 decimal places
The flagpole is 15.92 metres, approx.
21 ft how is the equation to give you this result
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
It is approx 36.6 ft.
84 feet tall
1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?
It works out as 3.75 feet
The flagpole is 24 feet tall.Assuming their shadows align exactly, they form similar triangles andh/32 = 6/8Mutiply both sides by 32h = 192/8 = 24
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.