h=vot+(1/2)gt2, vo=0 h=(1/2)gt2 t2=2h/g t=sqrt(2h/g)=sqrt(2x490/9.8)=sqrt(100)=10 seconds
240 ft
-- At the beginning of the time, the falling speed of the stone is zero.-- After 3.30 sec, its falling speed is 32.34 meters per second (Acceleration of gravity.)-- Its average falling speed is 1/2(0 + 32.34) = 16.17 meters per second.-- The distance it falls is (average speed) x (time) = (16.17) x (3.30) = 53.361 meters = 175.2 feet(These same steps lead to the formula H = 1/2 G T2 = (0.5) (9.8) (3.3)2 = 53.361)
Let Vo = initial velocity = 0 (m/s) x = vertical displacement t = time and a = gravitational constant = 9.8 meters per second squared (m/s2) x= initial velocity * time + 1/2 acceleration * time squared = Vot + (1/2)at2 = (0*3.1) + (1/2)(9.8)(3.1)(3.1) = 47.089 meters (metric) = 154.5 feet (English conversion)
The sound moves in a second 340 metres. That is in 3.8 seconds 1292 metres. But because there is the way down to the ocean and back to the ears of the stone dropper, the distance must be half of it. The cliff is 646 metres high.
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
240 ft
Ignoring any effects due to air resistance, the speed of the stone is zero at the instant it's dropped, and increases steadily to 78.98 meters per second when it hits the ground. The velocity is directed downward throughout the experiment.
-- At the beginning of the time, the falling speed of the stone is zero.-- After 3.30 sec, its falling speed is 32.34 meters per second (Acceleration of gravity.)-- Its average falling speed is 1/2(0 + 32.34) = 16.17 meters per second.-- The distance it falls is (average speed) x (time) = (16.17) x (3.30) = 53.361 meters = 175.2 feet(These same steps lead to the formula H = 1/2 G T2 = (0.5) (9.8) (3.3)2 = 53.361)
The acceleration will be equal to the acceleration due to gravity. Unless otherwise stated, one can assume this to be 9.81 meters/seconds It has nothing to do with the mass of the stone.
I believe it is called an "Antipodal Spike".
Let Vo = initial velocity = 0 (m/s) x = vertical displacement t = time and a = gravitational constant = 9.8 meters per second squared (m/s2) x= initial velocity * time + 1/2 acceleration * time squared = Vot + (1/2)at2 = (0*3.1) + (1/2)(9.8)(3.1)(3.1) = 47.089 meters (metric) = 154.5 feet (English conversion)
"Dropped like a stone" is a simile because it uses "like" to compare the action of dropping to a stone.
Stone Mountain, Georgia's elevation doesn't even equal half a mile. It is 1,043 feet (318 meters) above sea level
in Europe
The building is h=.5 gt^2 meters tall; that is = .5x9.8 x25 =122.5 meters.
Cliff Winfield Stone has written: 'Conservation in the schools' -- subject(s): Natural resources, Study and teaching
The sound moves in a second 340 metres. That is in 3.8 seconds 1292 metres. But because there is the way down to the ocean and back to the ears of the stone dropper, the distance must be half of it. The cliff is 646 metres high.