176.4 meters
29.4/3=9.8m/s2
,033
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
The sound moves in a second 340 metres. That is in 3.8 seconds 1292 metres. But because there is the way down to the ocean and back to the ears of the stone dropper, the distance must be half of it. The cliff is 646 metres high.
176.4 meters
The height of the cliff can be calculated using the formula for free fall: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time (6 seconds). Plugging in the values, we get h = (1/2)(9.8 m/s^2)(6 s)^2 = 176.4 meters. Therefore, the height of the cliff is 176.4 meters.
An object dropped from a height without any initial velocity, a skydiver falling towards the ground before deploying their parachute, and a rock falling off a cliff are all examples of free fall.
The volleyball will NOT hit the ground with greater anything. Assuming that the soccer ball is the same spherical diameter and greater mass than the volleyball it will hit the ground with greater velocity and greater impact.
Jumping off a cliff typically results in a swift death due to the impact with the ground below. The speed of death would depend on the height of the cliff, with greater height leading to more force upon impact.
Using the horizontal distance and horizontal velocity of the ball, you can calculate the time it took for the ball to reach the ground. Then, you can use the time and the vertical acceleration due to gravity to find the height of the cliff using the equation: height = (1/2) * gravity * time^2. In this case, the height of the cliff would be approximately 11.3 meters.
the height restriction for it is about 1.4m
29.4/3=9.8m/s2
,033
The foot of a cliff is the bottom or lower end of a space or object where the cliff meets the ground or the sea.
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
A cannonball fired horizontally and one dropped from the height of the muzzle simultaneous with the shot will hit the ground at the same instant, provided only that the ground under the muzzle and the ground where the shot lands are at the same elevation, i.e. the shot was not fired off the edge of a cliff or into the side of a mountain. To solve this kind of problems, it often helps to separate the movement, or the speed, into vertical and horizontal components. In this case, the vertical component of the speed is the same.