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Q: How long is the diagonal of a square if the side is 24?

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The answer will depend on WHAT is 24 inches: the side, the diagonal, some other aspect.The answer will depend on WHAT is 24 inches: the side, the diagonal, some other aspect.The answer will depend on WHAT is 24 inches: the side, the diagonal, some other aspect.The answer will depend on WHAT is 24 inches: the side, the diagonal, some other aspect.

Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet

24 ÷ 4 = 6 (length of each side of the square).

Each side is six inches long.

6 inches.

FG should be 12.2²-12²(half of 24)=4.84 then square root it which equals 2.2 and then you double it so the answer is 4.4

The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm

24 inches

There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13

38.42 feet.

43.26661530556787

Use Pythagoras' theorem: 33.9411255 or about 34 feet

By Pythagoras, the other side is 24 inches long. So the perimeter is 2*(10+24) = 2*34 = 68 inches.

To find the answer, use Pythagorean theorem. You have a and b, and want c. c=square root of 16 squared plus 24 squared = 28.8444

You use the Pythagorean Theorem, which says that the square of the hypotenuse of a right triangle is the sum of the squares of the other two sides. Two adjacent sides of a square (or any rectangle) together with a diagonal form a right triangle. In the case of a square, the triangle is isosceles. Calling the length of a side of the square (17 inches) one unit, the theorem tells us that the hypotenuse is the square root of 2 units. Therefore the diagonal of the square is 17 times the square root of 2 inches, which is about 24 inches.

diagonal^2 = 16^2 + 24^2 = 256 + 576 = 832 Therefore diagonal is square root of 832 = 28.8444 feet

Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13

If it's a square then using Pythagoras' theorem the diagonal works out as about 34 feet

The diagonal of a 12' x 24' rectangle is approx 26.8'.

24cm (4 sides x 6 = 24)

The formula for an area of a square is A = s2, where A is the area, and s is the length of each side. Since we have 24 units as the length here, the answer is 24 x 24 = 576 square units.

That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.

24 feet because you count each side

A square has 4 sides. Perimeter is the sum of its sides. So 24/4 = 6 cm (1 side). Area of square is (side*side)= 6*6 = 36cm2

The apothem of a square is equal to one half of the length side of the square. So the side length of the square is 24 (2 x 12). Thus, the area of the square is 576 (24^2).