Diagonal = square root of (24 squared + 26 squared)
and that is square root of (576 + 676)
and that is square root of (1252)
and that is 35.38 feet
The diagonal of a 12' x 24' rectangle is approx 26.8'.
Using Pythagoras theorem: 53.665' correct to 3 dp
46.648 ft
12 square feet.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
38.42 feet.
43.26661530556787
The diagonal of a 12' x 24' rectangle is approx 26.8'.
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
The diagonal is about 28.3 feet.
Using Pythagoras theorem: 53.665' correct to 3 dp
Diagonal = 36.9 feet
No. The diagonal of the rectangle is a little over 32.2, and nothing that long can fit into a circle with a diameter of 27.
The diagonal is approximately 38.42 feet.
Using Pythagoras' theorem it is 26 inches in length
36.8782 ft
46.648 ft