Diagonal = square root of (24 squared + 26 squared)
and that is square root of (576 + 676)
and that is square root of (1252)
and that is 35.38 feet
The diagonal of a 12' x 24' rectangle is approx 26.8'.
Using Pythagoras theorem: 53.665' correct to 3 dp
46.648 ft
12 square feet.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
43.26661530556787
The diagonal of a 12' x 24' rectangle is approx 26.8'.
To find the diagonal measurement of a rectangle with dimensions 24 by 32, you can use the Pythagorean theorem. The diagonal ( d ) can be calculated using the formula ( d = \sqrt{(24^2 + 32^2)} ). This gives ( d = \sqrt{(576 + 1024)} = \sqrt{1600} = 40 ). Therefore, the diagonal measurement is 40 units.
The diagonal is about 28.3 feet.
To find the diagonal of a rectangle with dimensions 24 feet by 36 feet, you can use the Pythagorean theorem. The diagonal (d) can be calculated using the formula (d = \sqrt{(length^2 + width^2)}). Plugging in the values: (d = \sqrt{(24^2 + 36^2)} = \sqrt{(576 + 1296)} = \sqrt{1872} \approx 43.27) feet. Therefore, the diagonal is approximately 43.27 feet long.
Using Pythagoras theorem: 53.665' correct to 3 dp
Diagonal = 36.9 feet
No. The diagonal of the rectangle is a little over 32.2, and nothing that long can fit into a circle with a diameter of 27.
The diagonal is approximately 38.42 feet.
Using Pythagoras' theorem it is 26 inches in length
Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
36.8782 ft