To find the area of one side of the suitcase, we need to determine its width using the Pythagorean theorem. Given that the length is 24 inches and the diagonal is 30 inches, we can calculate the width (w) as follows: ( w = \sqrt{30^2 - 24^2} = \sqrt{900 - 576} = \sqrt{324} = 18 ) inches. Therefore, the area of one side is ( 24 , \text{inches} \times 18 , \text{inches} = 432 , \text{square inches} ). Thus, 432 square inches of material is needed to cover one side of the suitcase.
Any rectangle that measures 12-in x 13-in has a diagonal ofsqrt(122 + 132) = 17.692 inches (rounded)
Well, honey, an 80 linear inches suitcase is typically considered oversized by most airlines. It's like trying to squeeze a watermelon into a grapefruit-sized space. You might want to check with your airline to see if they'll let you bring that bad boy on board without charging you an arm and a leg.
Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches
A square with 2-inch sides has a diagonal of: 2.828 inches.
The diagonal is about 16.97 inches long.
A suitcase that measures 62 linear inches is typically considered a medium-sized suitcase.
6.2
The largest suitcase you may take onboard a flight measures 24" x 16" x 10" or 45 linear inches.
26.4 inches for the diagonal.
Any rectangle that measures 12-in x 13-in has a diagonal ofsqrt(122 + 132) = 17.692 inches (rounded)
Well, honey, an 80 linear inches suitcase is typically considered oversized by most airlines. It's like trying to squeeze a watermelon into a grapefruit-sized space. You might want to check with your airline to see if they'll let you bring that bad boy on board without charging you an arm and a leg.
The diagonal is 14 inches.
diagonal is 13 inch length of the rectangle of 12 and 5 inches sides
Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches
No, a 28-inch suitcase is not considered to be 62 linear inches.
The square of the diagonal is (652+692)=8986 The diagonal is then the square root of 8986=94.79...
A square with 2-inch sides has a diagonal of: 2.828 inches.