t = 2*pi*sqrt(l/g)
Therefore, if t = 1 then 1 = 2*pi*sqrt(l/g)
so that l = g/(4*pi2) = g/157.9 approx
Taking g = 9.81 ms-2, this gives l = 0.0621 metres = 6.21 cm
If the length of the second pendulum of the earth is about 1 meter, the length of the second pendulum should be between 0.3 and 0.5 meters.
The period depends on both the length of the pendulum and the force due to gravity. They are related by Huygen's law, T = 2π√(l/g). Assuming a gravity of 10Nkg-1 (roughly equal to Earth's 9.81 and a common approximation) it would need to be 2.5/pi2, or about 0.253099 metres.
In measuring the period of a pendulum's motion with a stopwatch, you can best minimize the influence of reaction time by measuring period at the maximum swing point, i.e. the point where the pendulum stops and then reverses. It is at that point that the pendulum is moving the slowest. You should also make your line of sight be perpendicular to the swing, in order to minimize parallax error; and you should have a mark of some kind that you can move around to the peak value, then recording the period between successive peak values.
At the extremities of the pendulum's swing, the sand leaving the bob could exert a force on the bob. Provided that this force is negligible and also, provided the mass of the bob (with or without the sand) is large compared with the rest of the pendulum, the time period should not be affected.
wind resistance cannot be ignored in considering a simple pendulum. The wind resistance will be proportional to a higher power of the velocity of the pendulum. A small arc of the pendulum will lessen this effect. You could demonstrate this effect for yourself. A piece of paper attached to the pendulum will add to the wind resistance, and you can measure the period both with and without the paper.
If the length of the second pendulum of the earth is about 1 meter, the length of the second pendulum should be between 0.3 and 0.5 meters.
The period depends on both the length of the pendulum and the force due to gravity. They are related by Huygen's law, T = 2π√(l/g). Assuming a gravity of 10Nkg-1 (roughly equal to Earth's 9.81 and a common approximation) it would need to be 2.5/pi2, or about 0.253099 metres.
In measuring the period of a pendulum's motion with a stopwatch, you can best minimize the influence of reaction time by measuring period at the maximum swing point, i.e. the point where the pendulum stops and then reverses. It is at that point that the pendulum is moving the slowest. You should also make your line of sight be perpendicular to the swing, in order to minimize parallax error; and you should have a mark of some kind that you can move around to the peak value, then recording the period between successive peak values.
A lift in free fall is the same as a lift with no gravity (e.g. in space), i.e. accelleration due to gravity, g = 0 ms^-2. Now your intuition should tell you what's going to happen but even if it doesn't you can plug this value into your equation for the pendulum's period to find out what happens.
The time it takes for a pendulum to make one swing is almost exactly the same regardless if it swings thru any small angle. Once the angle starts getting large, like more then 10 deg, the difference in swing time becomes noticable. If you use a pendulum as a clock,so each second is one swing, then if you start the pendulum swinging at about 10 deg it will continue to be one second per swing even as it runs down to a smaller swing angle.
At the extremities of the pendulum's swing, the sand leaving the bob could exert a force on the bob. Provided that this force is negligible and also, provided the mass of the bob (with or without the sand) is large compared with the rest of the pendulum, the time period should not be affected.
It should look exactly as it does when you are not on your period.
The only choice is to change the effective length of the rod.The period doesn't depend directly on the weight of the bob.
wind resistance cannot be ignored in considering a simple pendulum. The wind resistance will be proportional to a higher power of the velocity of the pendulum. A small arc of the pendulum will lessen this effect. You could demonstrate this effect for yourself. A piece of paper attached to the pendulum will add to the wind resistance, and you can measure the period both with and without the paper.
This is done in order to get unbalanced force act on the pendulum. A torque will act due to gravitation of the earth and the tension in the string as they then act at different points and opposite direction on the pendulum. Have the forces act at the same point, the formation of torque would have been ruled out and the pendulum would not swing.
Not exactly.. your period can occur as late as the 4th sugar pill
well, you could simply pull it away from its centre of equilibrium (the point where the pendulum is when its stationary), and release it. Then you just count how many seconds it takes to make one complete oscillation. Note, one oscillation isn't the time for the pendulum to swing to the other side, but is the time taken for the pendulum to return to the side it was initially released from.Note: the greater the angle of the swing, the greater the speed with which the pendulum will swing, but in the absence of air resistance, the period should remain the same with the same pendulum, and because air resistance is all around us, when we move through the air, and is proportional to the speed squared, this will begin to effect the result, by slowing down the pendulum. Therefore a pendulum only obeys SHM for smaller displacements from the point of central equilibrium, or another way of putting that is for smaller angles of pendulum displacment.