Want this question answered?
195 joule..
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
1 second
A 50 watt heater is major over kill for a 3 gallon tank, a 10 watt heater is more than enough for a tank that size. You will nuke your aquarium very quickly the first time the 50 watt heater sticks on, with a 10 watt heater if it sticks on the aquarium temp will only raise a degree or two.
what is the answer to this
The specific heat of a substance is the heat required to raise the temperature of one gram of the substance one degree centigrade.
4186 Joules per liter per deg C. Not clear if we are raising the temperature BY 135 deg or TO 135 deg. So the answer is 4186 x 100 x rise in temperature. (Joules).
It takes 8.33 BTU to raise the temperature of water 1 degree F.
q(Joules) = mass * specific heat * change in temperature q = 32.0 grams H2O * 4.180 J/gC *(54.0 C - 12.0 C) = 5617.92 Joules this is, of course 5.62 kilojoules
The question is : A 2000W electric heater supplies energy to 0.5kg copper kettle containing 1kg of water. calculate time taken to raise the temperature by 10 degree
A calorie is the amount of heat required to warm 1 gram of water one degree Centigrade. A Calorie spelt with a big "C" is a kilocalorie and is used in evaluating food energy. It is the heat required to raise 1 kilogram of water one Centigrade degree. On an energy basis a calorie is 41 840 000 ergs.
It takes 2.46 calories of heat to raise the temperature of one gram of ethyl alcohol. Calories are the energy available from the metabolism of a food.