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How long will it take 1 watt to heat 1 liter of water 1 degree centigrade?
Roughly 4200 seconds, since the specific heat of water is around 4.2J/gK (ie it takes 4.2 joules to raise 1 gram by 1 Kelvin); 1 litre = 1000 grams, 1 Celcius (centigrade) = 1K, 1W = 1J/s.
How many watts are required to raise water through 40 degree centigrade?
Since watt is a unit of power (how fast energy is transferred), you can do this with almost any amount of power - as little or as much as you want, depending on how fast you want to heat the water. The time it takes will depend on the initial temperature, the amount of water, and the power.
How many calories does it take to heat 1 liter of water 1 degree?
It takes 1000 calories to heat 1 litre of water 1 degree C.
What is the volume of one liter water?
The volume of 1 liter of water is 1 liter.
How many calories are needed to raise the temperature of 10 g of water from 25 C to 35 C?
100 calories. 1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of 1 by 1 degree Celsius. So, if you need to raise 10 grams of water 1 degree, you would need 10 calories of energy. If you needed to raise those same 10 gram by 10 degrees, you'll need 10 * 10, or 100 calories.
How much energy is required to raise the temperature of one liter of water 1 degree centigrade?
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
How long will it take 1 watt to heat 1 liter of water 1 degree centigrade?
Roughly 4200 seconds, since the specific heat of water is around 4.2J/gK (ie it takes 4.2 joules to raise 1 gram by 1 Kelvin); 1 litre = 1000 grams, 1 Celcius (centigrade) = 1K, 1W = 1J/s.
What is is the amount of heat needed to raise the temperature of one kilogram of water one degree centigrade.?
The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius. To raise the temperature of one kilogram (1000 grams) of water by one degree Celsius, it would require approximately 4180 Joules of heat energy.
What is the boiling point of 2 liter of water in centigrade?
At 1 atmosphere of pressure, the boiling point of water is 100 degrees Celsius (Centigrade). The volume of water does not matter.
What degree does it take to freeze water?
At Zero degrees centigrade for pure water.
What integer represents the boiling point of water in degree centigrade?
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What is Anomalous expansion of water?
The expansion of water when it is cooled from four degree centigrade to zero degree centigrade is known as "anomalous expansion of water." The unusual behaviour of water, when it expands below 4° celsius to 0° is called anmalus expansion of water.
Time required to raise 1 degree centigrade in 1 liter of water?
To determine the time this will take, you need to know the rate at which heat is being added to the system. The specific heat capacity of a substance is the amount of energy required to raise the temperature of one gram of a substance one degree centigrade. For water at 25oC, the specific heat capacity is 4.184 J*g-1*oC-1. That is, if you have one gram of water, you must add 4.184 Joules of energy (heat) to raise the temperature one one degree centigrade. The time it takes for the temperature increase to happen depends on how quickly you add the 4.184 J. Adding heat at a rate of 1 Joule/second (which is equivalent to 1 Watt), it is easy to see that it will take 4.814 seconds to raise the temperature of the gram of water one degree centigrade. The first step to solving your problem, then, is to make your data units compatible with your known constants. We need to convert volume to mass. We do this by means of density. The density of liquid water at standard temperature and pressure is 1g/mL. 1L H2O *1000mL/1L *1g H2O/mL H2O= 1000g H2O Then, to find the amount of energy required to change the temperature of the mass, we use the specific heat. 1000g H2O *4.184J/(g*K)= 4184 J/oC Note the units on this last value. They give the amount of energy needed required per degree centigrade of change in the temperature. That is, it requires 4814J to change the temperature of 1000g H2O one degree centigrade. Given the time rate of heat transfer into the system, you can find the time required to make the change. If, for instance, your heat exchange rate is 5 Watts (J/s), you would have 4184 J/oC * 1 second/5 Joules = 836.8 s/oC This value allows you to calculate the time required for any change in temperature simply by multiplying the number of degrees centigrade temperature change. For one degree, we find 836.8 s/oC *1oC = 836.8s
How much energy is required to raise 1 cubic centimeter of water 1 degree?
It takes 1 calorie of energy to raise 1 gram of water by 1 degree Celsius. Since 1 cubic centimeter of water is equivalent to 1 gram, it would take 1 calorie of energy to raise 1 cubic centimeter of water by 1 degree Celsius.
What is the word origin of the word calorie?
"Calorie" comes to us from Latin "calor", meaning "warmth". A calorie is the energy required to raise the temperature of one gram of water by one degree centigrade.
The number of kilojoules needed to raise the temperature of 32.0 g of water from 12.0 degree centigrade to 54.0 degree centigrade is?
q(Joules) = mass * specific heat * change in temperature q = 32.0 grams H2O * 4.180 J/gC *(54.0 C - 12.0 C) = 5617.92 Joules this is, of course 5.62 kilojoules
Why is the centigrade scale named the centigrade scale?
It is based on units of ten, and the boiling point of water on the centigrade scale is 100 degrees. That's what centigrade means: Centi=100. Gradus=step or degree.
