To answer this question you need to provide both length and width. Example: 9'6" wide x 10' long.
Approximately 73 square feet.
To cover 100 square feet with 24x24 inch tiles, first convert the tile size to square feet. A 24x24 inch tile is 2x2 feet, which equals 4 square feet per tile. Therefore, to cover 100 square feet, you would need 100 ÷ 4 = 25 tiles. So, you need 25 tiles to cover 100 square feet.
Each tile covers 81 square inches. You have 1,296 square inches to cover. It will take 16 tiles to cover that area.
A tile measuring 2 foot by two foot (which, incidentally, is an unusually large tile) has an area of 4 square feet, so it would take 100 such tiles to cover a 400 square foot floor.
a 12 x 12 tile is 1 square foot. So, you would need 300 tiles to cover 300 square feet
Tiles that are two feet on a side cover 4 square feet. 378 of them cover 1512 square feet.
500/1.78 = 281 tiles
.375
It depends on how big the tiles are.
It would be 9 tiles wide by 12 tiles long. That gives you a total of 108 tiles.
Assuming you mean 16x16 inches tiles... 441 tiles would cover the area exactly
You would need 29 tiles of that size to cover that area (28.77 tiles) to be precise,
You would need a total of 92 tiles. It would take just over 91 tiles to cover the area given.
76.6 tiles
67 tiles.
To cover 720 sq feet of floor with 18" x 18" tile, you would need 320 tiles.
104.0625 tiles exactly (so - 105 tiles in all)