I'll presume that you meant "tiles" and the math answer is 228.25 title. Determined as follows: 16" X 16" = 256 sq. inches. There are 144 sq. inches in 1 square foot (12X12). 256 divided by 144 = 1.77 sq. feet. So one 16" by 16" tile covers 1.77 sq. feet. 404 sq. feet divided by 1.77 = 228.25. (Manufact. rate their tiles between 1.7222 & 1.775 because they are usually not precisely 16X16) Now from a contracting point of view this does not taken into account the grout joints that usually exist between each tile, the size of which is up to you, which would increase the surface area that each tile covers when grounted in place, which would reduce the number of tiles. It also does not it take into account breakage or waste which would increase the number of tiles. Most rooms don't allow for the use of only full tiles so you have to cut full tiles leaving some waste. Also tiles sometimes break in the box and when you try to cut them. To play safe if you are looking to buy tile I'd buy a minimum of 250 tiles. Most suppliers allow you to return any un-used cases, so always buy extra. If this is your first tiling job I'd buy even more. Good luck
16x16 square feet = 256 square feet, so two tiles will suffice.
297 16x16-inch tiles.
141
.375
90 tiles.
l2 math.
130 ft2 / 16 ft2 = 8.125 tiles
Well, darling, if each tile is 16x16 square feet, then you just need to divide the total area (150 square feet) by the area of one tile (16x16 square feet) to get your answer. So, 150 divided by 16x16 equals about 5.86 tiles. But since you can't have a fraction of a tile, you'll need to round up to 6 tiles to cover that 150 square feet.
675 of them. Get extra for breakage.
150 16x16" tiles; you'll have a small part of one tile left over.
Assuming you mean 16x16 inches tiles... 441 tiles would cover the area exactly
125 16-inch tiles.