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Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77

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โˆ™ 2011-01-21 13:39:32
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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How many 2-digit numbers can be formed using the digits 1 3 7 if repetition of digits is allowed?
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Related questions

How many 3 digit numbers can be formed from the digits 1234?

64 if repetition is allowed.24 if repetition is not allowed.


How many 4 digit numbers can be made to give the sum of 6?

If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.


How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.


How many 3 digit number can be made using the digits 2 4 7 9?

24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.


How many 2-digit numbers can be produce using the digits 123456789 if repetition is not allowed?

-123456787


How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?

125


Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?

There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.


How man 7 digit combinations can be made using numbers 0 through 9?

10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.


How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?

290


How many 4-digit numbers are possible if the hundreds digit is 8 and if repetition of digits is allowed?

-4


How many even 3-digit numbers can be formed from digits 1 3 5 7 9 repetition allowed?

125 There are five choices for each of the three digits (since repetition is allowed). So there are 5*5*5=125 combinations.


What is the sum of all the four digit numbers formed using the digits 0 1 2 and 3 if repetition is allowed?

It is 415968.

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