24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.
If repetition of digits is allowed then we have:
For 3 repetitions, 4 three digit numbers.
For 2 repetitions, 36 three digit numbers.
So we have a total of 64 three digit numbers if repetition of digits is allowed.
2
44,332,211
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
Only one.
The biggest 4 digit number that can be made from using the digits of 850236, using a digit at most once, is 8653.
24
987,654,321
874321 is the largest number made from all these digits.
To form a 5-digit number using the digits 1, 2, 6, 7, and 9 without repetition, we can use all five digits. The number of different arrangements of these 5 digits is calculated by finding the factorial of the number of digits, which is 5!. Therefore, the total number of 5-digit numbers that can be formed is 5! = 120.
2
A delectable number has nine digits, using the numbers 1-9 once in each digit. The first digit of a delectable number must be divisible by one. The first and second digits must be divisible by two, the first through third must be divisible by three, etc. There has only been one delectable number discovered: 381654729.
Six: 234, 243, 324, 342, 423, and 432.
In decimal, a digit is one of the ten symbols that represent the numbers 0 to 9. A number can be made up of one or more digits. For example: 1 is a digit (as well as a number of course). 11 is a number made up of 2 digits.
To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
9876
To form a four-digit number using the digits 0, 1, 2, 3, 5, 6, and 7, we must ensure that the first digit is not 0 (to avoid creating a three-digit number). This leaves us with 6 options for the first digit (1, 2, 3, 5, 6, 7). For the remaining three digits, we can use any of the 7 digits (including 0) and can repeat digits. Thus, the total number of four-digit numbers is calculated as follows: (6 \times 7 \times 7 \times 7 = 6 \times 343 = 2058). Therefore, there are 2058 possible four-digit numbers.