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How many 2 digit numbers can be formed with 0 through 5 where 0 is the first digit and others can not be repeated?
Wiki User
∙ 13y ago
-- If 'zero' is always the first digit, then we're pretty darn sure that no other digit
can be repeated in the same 2-digit number, since there's only one digit left to
be filled in.
-- If 'zero' is always the first digit, then there are exactly six possible 2-digit numbers:
00
01
02
03
04
and
05.
Wiki User
∙ 13y ago
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How many 5 digits can be formed with digits 012345 divisible by 3 with digits not repeated?
0+1+2+3+4+5 = 15 so, if a 5-digit number, formed from these digits, is divisible by 3 it must exclude 0 or 3. If it excludes 0, all 5*4*3*2*1 = 120 permutations are valid. If it excludes 3, then 4*4*3*2*1 = 96 permutations are valid (the others start with a zero and so are 4-digit numbers). That makes a total of 120+96 = 216 numbers.
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How many 5 digits can be formed with digits 012345 divisible by 3 with digits not repeated?
0+1+2+3+4+5 = 15 so, if a 5-digit number, formed from these digits, is divisible by 3 it must exclude 0 or 3. If it excludes 0, all 5*4*3*2*1 = 120 permutations are valid. If it excludes 3, then 4*4*3*2*1 = 96 permutations are valid (the others start with a zero and so are 4-digit numbers). That makes a total of 120+96 = 216 numbers.
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