There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
There are 233 - 1 = 8,589,934,591 combinations, not including the null combination.
Three combinations: 23, 24 and 34
1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations
The number of combinations of 35 things taken 5 at a time is 35! / (5! * (35-5)! which is 35! / (5! * 30!). 35! / 30! is 35 * 34 * 33 * 32 * 31, and 5! is 120. After cancelling we are left with 7 * 34 * 11 * 4 * 31 which is 324,632
There are 234 - 1 combinations. Each one of the 34 numbers can either be in a combination or not in it. The two-fold choice gives 234 possible options. However, one of these consists of the option where in each case the choice is "not in it". So you have a null combination. Excluding that combination leaves 234 - 1. Remember that in a combination, the order of the numbers does not matter.
If not using the same number twice: 36x35x34x33x32= 45,239,040 If allowed to use all numbers up to 5 times: 36x36x36x36x36=60,466,176
To calculate the number of 6-number combinations from a pool of numbers 1-39, we can use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 39 (total numbers) and r = 6 (numbers chosen). Plugging these values into the formula, we get 39C6 = 39! / (6!(39-6)!) = 3,262,623 unique combinations.
there is 3 tens and 4 ones in the following number 34
1-36 are numbers, NOT digits. The number of combinations of 10 numbers out of 36 is 36*35*34*33*32*31*30*29*28*27/(10*9*8*7*6*5*4*3*2*1) which is 254,186,856
34 is a composite number.34 is a Composite Number (all whole numbers ending in four are composite).
( 36! )/( 32! ) ( 4! ) = (36 x 35 x 34 x 33)/(4 x 3 x 2) = 58,905