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How can you find the total number of 10 number combinations possible from digits 1-36?
Wiki User
∙ 13y ago
1-36 are numbers, NOT digits.
The number of combinations of 10 numbers out of 36 is
36*35*34*33*32*31*30*29*28*27/(10*9*8*7*6*5*4*3*2*1)
which is 254,186,856
Wiki User
∙ 13y ago
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Using 4 digits what is the total number of combinations for a 4 digit lock code?
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
What are the possible different combinations of numbers in four digits?
If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.
How many unique 6 digit combinations with the same 6 numbers and 6 characters like 012345 and ABCDEF?
Total of 720 combinations:1 --- 12 --- 23 --- 64 --- 245 --- 1206 --- 7207 --- 5040.......Notice that:A --- BC --- DE --- FG --- XIn this sequence, if you wanted to know "X", it would be equal to FxG, and that is the key to this sequence. Why does it happen?Well, if, lets see, for instance, if 2 digits (0 and 1) have a possible of two combinations (10 and 01), then 3 digits (0, 1 and 2) will have a possible of six combinations: 012021And equivelent, but switching 0 with either 1 or 2, making it repeat itself 3 times.Eventually, we will end up doing 2 (number of combinations with 2 digits) times 3 (number of digits of which we want to know the number of unique combinations possible), totallizing 6 (our wanted-to-know number)
How many license plates can be made using 3 letters followed by 4 digits?
In the English alphabet there are 26 letters. And there are 10 Arabic numerals (digits). For any arbitrary number of letters and numbers, the number of combinations can be found as the product of the number of possible symbols in each space, in this case: 26 * 26 * 26 * 10 * 10 * 10 * 10. Another way to approach it is to raise 26 by the number of letters, and 10 by the number of digits, and multiply those together. Here it would be 26 to the third power times 10 to the fourth power: 26 ^ 3 = 17576 10 ^ 4 = 10000 Total = 175,760,000
What is the equation to determine number of possible lock combinations?
In the simplest case, if A is the number of values a single element of a combination can have, and N is the number of elements in the combination, then the number of possible lock combinations is AN. For example: if you have a lock with a 4-digit numerical combination, any combination has 4 elements - the digits. Each digit can have 10 values - 0 through 9. So the total number of lock combinations is 104 or 10000. Another example: if you have the typical rotating combination padlock, a combination consists of three numbers, each of which can be 0-39. So the total number of combination shere is 403 or 64000. The calculation gets more complicated if the same number can't appear twice in the combination. In that case, there are A values for the first element, but only A-1 values for the second, A-2 values for the third, and so on. The formula in this case is A(A-1)(A-2)(...)(A-N+1) which can be written more concisely as A!/(A-N)!. For example: if you have the same rotating combination padlock as above, but know that the numbers in the combination are all different, there are 40*39*38 or 59280 possible combinations.
Using 4 digits what is the total number of combinations for a 4 digit lock code?
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
What are the possible different combinations of numbers in four digits?
If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.
How can you find the total number of 4-number combinations possible from digits 1-7?
*inclusive: 74 = 2401 *exclusive: 7*6*5*4 = 840
What combinations can you make with numbers 1 4 7 2 5 8 0?
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
How many unique 6 digit combinations with the same 6 numbers and 6 characters like 012345 and ABCDEF?
Total of 720 combinations:1 --- 12 --- 23 --- 64 --- 245 --- 1206 --- 7207 --- 5040.......Notice that:A --- BC --- DE --- FG --- XIn this sequence, if you wanted to know "X", it would be equal to FxG, and that is the key to this sequence. Why does it happen?Well, if, lets see, for instance, if 2 digits (0 and 1) have a possible of two combinations (10 and 01), then 3 digits (0, 1 and 2) will have a possible of six combinations: 012021And equivelent, but switching 0 with either 1 or 2, making it repeat itself 3 times.Eventually, we will end up doing 2 (number of combinations with 2 digits) times 3 (number of digits of which we want to know the number of unique combinations possible), totallizing 6 (our wanted-to-know number)
If you wanted to know how many 5 digit combinations you could make using only 2 digits how would you solve this?
Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.
How many comvinationa to a 3 wheellock with digits 0 to 9?
There are 10 digits from which the first number can be selected, 10 digits from which the second number can be chosen and 10 from which the third number can be picked. This gives you a total number of combinations of 10 x 10 x 10 = 1000.
What are all of the possible numeric combinations using 1-5 starting with 15?
As the number has to start with 15, we have only 3 remaining digits to work with. There are 3 possible options for the first digit. Then out of each of these, 2 possible options for the second digit, and one option for the last. This means that in total there are 3x2x1 (6) possible combinations. These are: 15234 15243 15324 15342 15423 15432
How many combinations can you make with 5 digits only using 2 and 4?
Each of the 5 digits has two possibilities. So the total number of possible combinations is2 x 2 x 2 x 2 x 2 = 32 .(Another way to ask the same question is: How many binary numbers can you write with 5 bits ?)
How many combinations are there in a 4 digit number with no repreats?
Assuming that the digits 0-9 are available, the answer is 5040. This is because for the first digit you can pick any of the original 10 digits. For the second you can have any otherdigit, so 9 possible choices. The third follows the same rule, so has 8 possibilities, and the forth digit, 7.This means that the total number of combinations is 10 x 9 x 8 x 7 = 5040
How many digits in 0.0933?
Total number of digits = 5
How can you find the total number of 4 number combinations possible from digits 1-24?
If no number can be repeated, and the sequence of the numbers doesn't matter (so 1-2-3-4 is the same as 4-3-2-1), the answer is 24 x 23 x 22 x 21 = 255,024. The equation says there are 24 possible choices for the first number, 23 possible choices for the second number, 22 for the third and 21 for the fourth.
