Presuming base 10 (aka, all numbers are between 0-9), 1+(10^3/10) so 101.
Edit: Changed the exponential analysis to emphasis the fact that 10 9's occur in 100 10's. Some result though.
997 is the last 3 digit prime number
no
You line up the last numbers and then add it!
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
1155
No because its last digit is 6 which is an even number. Odd numbers have 1, 3, 5, 7, 9 in its last digit or in the ones digit. Examples: 3, 11, 25,789
1
There are 54 such numbers.There are 54 such numbers.There are 54 such numbers.There are 54 such numbers.
The number 153 is an odd number. It's because the last number 3 is an odd number..... I hope you understand....
The largest 3-digit number=999 the smallest 3-digit number=100 total number of 3 digit number=(999-100)+1 =899+1=900
no, as it is an odd number. (3 as the last digit)
No. Consider 13 or 23.