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Q: How many 3 digit numbers are there that contain at least 1 seven?
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How many seven digit numbers contain the number seven at least once?

4,748,472 Confirmed using the following C# function string sTemp; int total = 0; for (int i = 1000000; i < 10000000; i++) { sTemp = i.ToString(); if (sTemp.Contains("7")) { total++; } } label1.Text = total.ToString();


How many seven digit numbers are there when 0 and 4 cannot be the leading number?

If the number can contain repeated digits, the answer is 800000. Without repetition, there are 483840.


What is the digit of seven numbers?

1 million 1,000,000


How many two digit numbers can you form using the digits 1235679 with repetition allowed?

You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.


What 3 digit numbers have one to seven as factors?

420 and 840


What is the smallest seven - digit number that you can form using the combination of numerals 1 and 2?

Assuming a seven digit whole number: 1,111,111. But if you have to use at least one (2) digit, then 1,111,112.


The probability that a number selected from random between 100 and 999 both inclusive will not contatin the digit 7?

For me I think it is conceptually easier to think about the probability that the number will contain the digit seven (and the probability that it does not contain the digit 7 is simply one minus the probability that it does). P(number will contain 7) = P(number is in the seven hundreds) + P(number is not in seven hundreds)*[P(number is in the X hundred seventies)+P(number is not in the X hundred seventies)*P(number ends in seven)] So essentially I am considering all of the numbers in the range that start with seven (i.e., are in the seven hundreds), then all of the numbers in the range that aren't in the seven hundreds but have a 7 in the tens place (i.e., the 170s, 270s, etc., and finally all the numbers that don't have a 7 in the hundred or tens place, but that end in 7). Plugging the numbers into my formula above, I get (100/900)+(800/900)*((10/100)+(90/100)(1/10)) = 7/25 is probability that the number does contain a 7, and 1-(7/25)=18/25 is probability that it does not.


How many numbers between 100 and 300 have a digit sum of 4?

Seven of them.


What is the smallest seven digit number that you can form using the combination of numerals 1 and 2 only?

Assuming a seven digit whole number: 1,111,111. But if you have to use at least one (2) digit, then 1,111,112.


How many seven-digit telephone numbers are possible if the first two digits cannot be ones or zeros?

That makes:* 8 options for the first digit * 8 options for second digit * 10 options for the third digit * ... etc. Just multiply all the numbers together.


How many seven digit numbers are there?

9,000,0009,999,999 is the last 7 digit number1,000,000 is the first 7 digit numberwhen you subtract the first from the last and add one you get the above answer.


Odd numbers in the seven hundreds?

Same as the odd numbers anywhere else, except the first digit is always "7"