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Q: How many seven digit numbers contain the number seven at least once?

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27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797

271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.

what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?

The largest six digit number period is 999999. The largest number meeting your criteria is 998949.

We are to calculate the number of 1-digit to 6-digit numbers (i.e. numbers less than one million) that have at least one 1. Let's divide this into six cases by the number of digits in the number.For one digit numbers, the only number is 1 - 1 such number.For two digit numbers, we can find the number which do not contain a 1 more easily. There are 8 possible digits for the tens place (0 and 1 are not allowed), and 9 digits for the ones place (1 is not allowed). Thus we have 8 * 9 = 72 which do not work. There are 90 two digit numbers, so 90 - 72 = 18 such numbers.For three digit numbers, we will proceed in the same manner. There are 900 total 3 digit numbers, of which 8 * 9 * 9 = 648 numbers which do not contain a 1. The remaining 900 - 648 = 252 numbers contain at least 1 one - 252.For four digit numbers, continuing in the same manner we have 8 * 9 * 9 * 9 = 5832 which are not good out of the 9000 total. So, 9000 - 5832 = 3168.For five digit numbers, we have 8 * 9 * 9 * 9 * 9 = 52488. The remaining 90000 - 52488 = 37512 are good.For six digit numbers, we have 8 * 9 * 9 * 9 * 9 * 9 = 472392. The reamining 900000 - 472392 = 427608 are good.Finally, adding all of the totals, we have 1 + 18 + 252 + 3168 + 37512 + 427608 = 468,559 numbers between 1 and 999999 which contain at least 1 one.

Related questions

252

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252

27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797

46000

271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.

i think alot like 100 at least

what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?

There are 9000 4 digit numbers Find 4 digit numbers that are all different from 1 find 4 digit numbers that are all different from 1 The thousands digit has 8 ways to choose, hundreds, tens, and units all have 9 ways => there are 8 x 9 x 9 x 9 = 5832 digits => 4 digit numbers contain at least 1 digit 1 = number of 4 digit numbers , the number of 4 digit numbers is different by digit 1 =9000 - 5832 = 3168 numbers

2000.The smallest four-digit number there can be is 1000. So, add 1000 and 1000 to get 2000, then least sum you can get when adding two four-digit numbers.

The greatest two-digit prime number is 97. The lowest two-digit prime number is 11. The product of the two numbers is equal to 1067.

The largest six digit number period is 999999. The largest number meeting your criteria is 998949.

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