You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
4,748,472 Confirmed using the following C# function string sTemp; int total = 0; for (int i = 1000000; i < 10000000; i++) { sTemp = i.ToString(); if (sTemp.Contains("7")) { total++; } } label1.Text = total.ToString();
How many two digit numbers are there in which the tens digit is greater than the one’s digit ?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
There are 84 such numbers.
252
Seven of them.
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
16, 25, 34, 43, 52, 61, 70 Seven of them.
4,748,472 Confirmed using the following C# function string sTemp; int total = 0; for (int i = 1000000; i < 10000000; i++) { sTemp = i.ToString(); if (sTemp.Contains("7")) { total++; } } label1.Text = total.ToString();
1 million 1,000,000
That makes:* 8 options for the first digit * 8 options for second digit * 10 options for the third digit * ... etc. Just multiply all the numbers together.
It would be from 1111111 to 9999999, and because 9999999 - 1111111 = 8888888, the answer is 8888888.
How many two digit numbers are there in which the tens digit is greater than the one’s digit ?
Any pair of digits (not including 0), can be used to generate 14 four-digit numbers. If one of the digits is 0, only seven will start with a non-zero digit.
None. 3 digit numbers are not divisible by 19 digit numbers.
Seven: 100 150 180 225 300 450 900.