(9 x 8 x 7) = 504
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
6 possible 3 digit combonations
a lot
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
-24686
2
There are 60480 numbers.
210
To form a 3-digit number using the digits 5, 6, and 8, we can use each digit in any position. Since we have three digits and they can be repeated, we have 3 choices for the first digit, 3 choices for the second digit, and 3 choices for the third digit. Therefore, the total number of 3-digit numbers is (3 \times 3 \times 3 = 27).
There are 504 of them.
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
To form a 4-digit number using the digits 2, 6, 9, and 5 without repeating any digit, you can use all four digits. The number of ways to arrange 4 digits is calculated as 4! (4 factorial), which equals 24. Therefore, you can form 24 different 4-digit numbers with the numerals 2695 without repeating any digit.