Q: If using 7 single digit numbers how many different combinations can you get?

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56 combinations. :)

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

66

There are 1140 five digit combinations between numbers 1 and 20.

5,040

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56 combinations. :)

9

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

To calculate the number of 6-digit combinations using 20 numbers, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 20 (the total number of numbers) and r = 6 (the number of digits in each combination). Plugging these values into the formula gives us 20C6 = 20! / 6!(20-6)! = 38,760 unique 6-digit combinations that can be formed using 20 numbers.

66

15

10,000

If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.

If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.

10!/3! = 604800 different combinations.

There are 1140 five digit combinations between numbers 1 and 20.

5,040