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How many different 2 digit numbers can you form using the digits 1 2 3 5 6 7 and 9 with repetition allowed?
10
What is the smallest five digit number you can form with the digits 0 1 2 3 and 4 if repetition of digits is allowed?
It is 10000.
How many two digit numbers can be formed with the digits 0123456789 if repetition of digits are not allowed?
To form a two-digit number using the digits 0-9 without repetition, the first digit (the tens place) can be any digit from 1 to 9 (9 options), since a two-digit number cannot start with 0. The second digit (the units place) can then be any of the remaining 9 digits (including 0 but excluding the first digit). Therefore, the total number of two-digit numbers that can be formed is 9 (choices for the first digit) multiplied by 9 (choices for the second digit), resulting in 81 possible two-digit numbers.
How many 5 digit numbers can be made using the digits 12679 if repetition isn't allowed?
To form a 5-digit number using the digits 1, 2, 6, 7, and 9 without repetition, we can use all five digits. The number of different arrangements of these 5 digits is calculated by finding the factorial of the number of digits, which is 5!. Therefore, the total number of 5-digit numbers that can be formed is 5! = 120.
How many 7-digit numbers can be formed using the digits 1 2 3 4 and 8?
To form a 7-digit number using the digits 1, 2, 3, 4, and 8, we can use any of the five digits for each of the seven positions. Since repetition of digits is allowed, the total number of 7-digit numbers is calculated as (5^7). Thus, (5^7 = 78125). Therefore, there are 78,125 possible 7-digit numbers.
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many different 2 digit numbers can you form using the digits 1 2 3 5 6 7 and 9 with repetition allowed?
10
How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 with repetition?
30 without repetition (6P2) 66 with repetition (12C2)
What is the smallest five digit number you can form with the digits 0 1 2 3 and 4 if repetition of digits is allowed?
It is 10000.
How many 5 digit numbers can be made using the digits 12679 if repetition isn't allowed?
To form a 5-digit number using the digits 1, 2, 6, 7, and 9 without repetition, we can use all five digits. The number of different arrangements of these 5 digits is calculated by finding the factorial of the number of digits, which is 5!. Therefore, the total number of 5-digit numbers that can be formed is 5! = 120.
How many six digit numbers can be formed using the digits 0123456789 Example equals 123456 or 098765?
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
How many 3-digit numbers can be formed using 0123456789 when repetition is not allowed?
-123456786
How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
How many 5 digit numbers can be formed if each one uses all the digits 0 1 2 3 4 without repetition?
If you allow the first digit to be zero, then you can form (5 x 4 x 3 x 2 x 1) = 120 numbers. If the first digit can't be zero, then you can only form (4 x 4 x 3 x 2 x 1) = 96 numbers.
How many different two digit numbers can you form using the digits 1 2 3 5 6 7 and 9 with repetition?
7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.
What is the largest four digit number you can form with the digits 2 3 4 and 7 if repetition of digits is allow?
7432
Given the digits 0-9... how many ways can you form a three digit even number without replacement of numbers?
If you're allowed to use zero as the first digit, then that would be 10!/7! = 10 * 9 * 8 = 720. If you're not allowed to use zero as your first digit, then it would be 9 * 9 * 8 = 648.
